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Damm [24]
3 years ago
9

In noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positi

on of one worker. The details of practical systems are complex, but we can present a simple example that gives you the idea. Suppose a machine 5.5 m away from a worker emits a persistent 90 Hz hum. To cancel the sound at the worker's location with a speaker that exactly duplicates the machine's hum, how far from the worker should the speaker be placed? Assume a sound speed of 340 m/s.
Physics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

7.39 m or 3.61 m

Explanation:

\lambda = Wavelength

f = Frequency = 90 Hz

v = Speed of sound = 340 m/s

Path difference of the two waves is given by

s_1-s_2=\frac{\lambda}{2}

Velocity of wave

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{340}{90}\\\Rightarrow \lambda=3.78\ m

s_1=s_2\pm\frac{\lambda}{2}\\\Rightarrow s_1=5.5\pm \frac{3.78}{2}\\\Rightarrow s_1=7.39\ m, 3.61\ m

So, the location from the worker is 7.39 m or 3.61 m

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A musician on a unicycle is riding at a steady 6.2 m/s while playing their well tuned oboe at an A above middle C (440 Hz). They
Verizon [17]

Answer:

The frequency of the beat is  f_t =  8Hz    

Explanation:

From the question we are told that

   The speed of the ride v = 6,2 m/s

   The frequency of the oboe is  f = 440Hz

    The temperature outside is  T = 27^oC

Generally the speed of sound generated in air is mathematically evaluated as

             v_s = 331  + 0.61 T

Substituting value

           v_s = 331 + 0.61 *27

           v_s = 347.47 \ m/s

The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as

                 f_a =  \frac{v_s }{v_s - v} f

substituting values

                f_a =  \frac{347.47 }{347.47  - 6.2} * 440                

               f_a =  448Hz

Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is  = 440Hz

    The beat frequency these musician here is mathematically evaluated as

                  f_t = f_a - f  

So               f_t = 448 - 440  

                  f_t =  8Hz    

3 0
3 years ago
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