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Evgen [1.6K]
3 years ago
15

Which TWO statements describe behaviors of particles that are related to the

Physics
1 answer:
kolezko [41]3 years ago
7 0

Answer: 1: (A) They allow electrons to move freely between them. 2: (C) they change their positions relative to one another.

Explanation:

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Which one of these is not a rock? A. granite B. Shale C. marble D. Diamond
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DIAMONDS are NOT rocks. Diamonds are minerals, rocks are made up of many different fragments of minerals.

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The main technical challenge faced by skiers is _________.
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3 years ago
Read 2 more answers
A boy is listening to the radio. The loudspeaker plays a musical note by vibrating 256 rimes esch second. How many times does th
Svet_ta [14]

Answer:

 f_tympanum = 256 Hz.

Explanation:

The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.

Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency

            f_tympanum = 256 Hz.

As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz

6 0
3 years ago
two metal plates are near each other. explain why they will not become charged until connected to a souce of potential differenc
scZoUnD [109]

Answer:

idk

Explanation:

7 0
3 years ago
  After giving an intense performance, a confused and disoriented flautist has wandered onto the motorway! They are playing a con
leva [86]
This is a Doppler effect. Generally, if you move to a frequency source, you would detect an increase in frequency and when you move away from a source you would detect a decrease.

For this question, before you pass them, you are actually approaching them, so you would hear a higher frequency than the constant 300 Hz they are playing at.

Using the condensed formula:

 f '   =   ((v <u>+</u> vd)/(v <u>+</u> vs)) * f

Where:  vd = Velocity of the detector.
              vs = Velocity of the frequency source.
              v   =  Velocity of sound in air.
              f '  =  Apparent frequency.
              f    =  Frequency of source.

v = 343 m/s,  vd = detector = 27.8 m/s,  vs = velocity of the source =0. (the flautists are not moving).
f = 300 Hz. 

There would be an overall increase in frequency, so we maintain a plus at the numerator and a minus at the denominator.

 f '   =   ((v + vd)/(v - vs)) * f

f '   =   ((343+ 27.8)/(343 - 0)) * 300
      =   (370.8/343)* 300 =  324.3

Therefore frequency before passing them = 324.3 Hz.

Cheers.
4 0
3 years ago
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