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2 years ago

How do you solve 3b(9b-27)=0

Mathematics

2 answers:

insens350 [35]2 years ago

3 0

Answer:0

Step-by-step explanation:3b(-27 + 9b) = 0

(-27 * 3b + 9b * 3b) = 0

(-81b + 27b2) = 0

pickupchik [31]2 years ago

3 0

Answer:

$b=3$ , or $0$

Step-by-step explanation:

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0$

$b=0\quad \mathrm{or}\quad \:9b-27=0$

$9b-27=0$ , $\mathrm{Add\:}27\mathrm{\:to\:both\:sides}.$

$9b-27+27=0+27$

$9b=27$

$\mathrm{Divide\:both\:sides\:by\:}9$

$\frac{9b}{9}=\frac{27}{9}$

$b=3$

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Read 2 more answers

PLEASE HELP!!

Ratling [72]

All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).

These probabilities are computed as 1 over all the possible outcomes.

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