Question

How do you solve 3b(9b-27)=0

Answer 1

Answer:0

Step-by-step explanation:3b(-27 + 9b) = 0

(-27 * 3b + 9b * 3b) = 0

(-81b + 27b2) = 0

Answer 2

Answer:

$b=3$, or $0$

Step-by-step explanation:

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0$

$b=0\quad \mathrm{or}\quad \:9b-27=0$

$9b-27=0$, $\mathrm{Add\:}27\mathrm{\:to\:both\:sides}.$

$9b-27+27=0+27$

$9b=27$

$\mathrm{Divide\:both\:sides\:by\:}9$

$\frac{9b}{9}=\frac{27}{9}$

$b=3$