Answer:
1) The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.
2) The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 0.045 mol/L.s.
Explanation:
<em>3NO(g) → N₂O(g) + NO₂(g).</em>
The rate of the reaction = -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt = Δ[NO₂]/Δt.
Given that: Δ[N₂O]/Δt = 0.015 mol/L.s.
<em>1) The rate of the overall reaction is?</em>
The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.
<em>2) The rate of change for NO is?</em>
The rate of change for NO = - Δ[NO]/Δt.
∵ -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt.
<em>∴ The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt </em>= 3(0.015 mol/L.s) = <em>0.045 mol/L.s.</em>
Answer:
By using magnet.
Explanation:
Put sand and zinc in the bowl.
Take a magnet an bring it close to the bowl.
The zinc from the sand will be attracted towards the magnet.
In this way it will be separated.
Answer:
612 K
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 306 K
Initial pressure (P₁) = 150 kPa
Final pressure (P₂) = 300 kPa
Volume = 4 L = constant
Final temperature (T₂) =?
Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:
P₁ / T₁ = P₂ / T₂
150 / 306 = 300 / T₂
Cross multiply
150 × T₂ = 306 × 300
150 × T₂ = 91800
Divide both side by 150
T₂ = 91800 / 150
T₂ = 612 K
Thus, the new temperature of the gas is 612 K
When energy is created without oxygen, the process is called anaerobic fermentation.
Answer:
Q = -1.318 KJ
Explanation:
We will use the assumption that this solution acts like water and thus we will use the specific heat capacity of water and when converting from mL to g, we will use the conversion like we do for water.
We are told that 50 mL of HCl reacts with 100 mL of NaOH.
Thus total mass; m = 50 + 100 = 150 mL
Converting to grams gives 150 g since we have assumed that the solution behaves like water.
We are given;
Initial temperature; T_i = 21.3° C
Final temperature; T_f = 23.4° C
ΔT = 23.4 - 21.3
ΔT = 2.1°C
Formula for quantity of heat is;
Q = mcΔT
c is specific heat capacity.
We will use c = 4.184 J/g°C since the solution is assumed to behave like water.
Thus;
Q = -(150 × 2.1 × 4.184)
Q = -1317.96 J
Negative sign is used because temperature was raised and thus reaction is exothermic.
Approximation to KJ gives; -1.318 KJ
