3 years ago

The interaction between electrical energy and magnetism has been an important

Physics

1 answer:

choli [55]3 years ago

4 0

Answer:

Maybe

Explanation:

I say maybe because it will help them still but not quite

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The net external force on a golf cart is 395.2 n north. if the cart has a total mass of 259.1 kg, what is the cart's acceleratio

yKpoI14uk [10]

Applying the Newton Second Law of motion that is F=ma
We have F=395.2N (North) and m=259.1Kg

Putting these values in the equation

395.2 = 259.1 x a than
for a = 395.2/259.1
a = 1.525 m/sec 2

8 0

3 years ago

A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the E

Sveta_85 [38]

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, $F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}$

Where $G=6.67*10^{-11}$ and $M=5.94*10^{24}$

$F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}$

F= 995.01142 then rounded off

F=995N

6 0

3 years ago

A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal

noname [10]

Answer:

$V=1.77m/s$

Explanation:

#Using the conservation of momentum , momentum before equals momentum after( $p=mv)$ .

-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.

Hence:

$9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\$

Hence, the final velocity of the cart and bag is 1.77m/s

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4 years ago

How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?

Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

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3 years ago

What does Hooke's law say about the relationship of a spring to the force applied to it?

hoa [83]

Answer:

Explanation:Hooke's law states that " if the elastic limit of an elastic material is not exceeded, the extension,e is directly proportional to the applied force or load.

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3 years ago