Hello!
C. KE ≈ 9120.105 J
D. m = 151.45 kg
Question C:
Calculate kinetic energy using the formula:
Substitute in the given mass. We have to convert kilometers to meters in order to solve.
Use the equation above:
KE = 1/2(1563)(11.67)
KE ≈ 9120.105 J
Question D:
Plug in the given Kinetic Energy and velocity to solve. Convert kilometers/hour to meters/second:
285 = 1/2(m)(1.94²)
570 = (1.94²)m
151.45kg = m
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m
OK. So you're pushing on the small box, and on the other side of it, the small
box is pushing on the big box. So you're actually pushing both of them.
-- The total mass that you're pushing is (5.2 + 7.4) = 12.6 kg.
-- You're pushing it with 5.0N of force.
-- Acceleration of the whole thing = (force)/(mass) = 5/12.6 = <em>0.397 m/s²</em> (rounded)
-- Both boxes accelerate at the same rate. So the box farther away from you ...
the big one, with 7.4 kg of mass, accelerates at the same rate.
The force on it to make it accelerate is (mass) x (acceleration) =
(7.4 kg) x (5/12.6 m/s²) = <em>2.936 N.</em>
The only force on the big box comes from the small box, pushing it from behind.
So that same <em>2.936N</em> must be the contact force between the boxes.
Answer
Given,
Magnetic field, B = 0.0000193 T
speed, v = 121 m/s
mass of electron, m = 9.11 x 10⁻³¹ Kg
charge of electron, q = 1.6 x 10⁻¹⁹ C
radius of the electron path, r = ?
r = 3.64 x 10⁻⁵ m
We know frequency is inverse of time period
d = v t
t = 1.889 x 10⁻⁶ s.
now, frequency
