The amount of solid does not affect how you are describing the solid so a is the answer
<h2>
Answer: (a)t=0.553s, (b)x=110.656m</h2>
Explanation:
This situation is a good example of the projectile motion or parabolic motion, in which the travel of the bullet has two components: x-component and y-component. Being their main equations as follows:
x-component:
(1)
Where:
is the bullet's initial speed
because we are told the bullet is shot horizontally
is the time since the bullet is shot until it hits the ground
y-component:
(2)
Where:
is the initial height of the bullet
is the final height of the bullet (when it finally hits the ground)
is the acceleration due gravity
<h2>Part (a):</h2>
Now, for the first part of this problem, the time the bullet elapsed traveling, we will use equation (2) with the conditions given above:
(3)
(4)
Finding
:
(5)
Then we have the time elapsed before the bullet hits the ground:
(6)
<h2>Part (b):</h2>
For the second part of this problem, we are asked to find how far does the bullet traveled horizontally. This means we have to use the equation (1) related to the x-component:
(1)
Substituting the knonw values and the value of
found in (6):
(7)
(8)
Finally:
Based on the calculations, the angle through which the tire rotates is equal to 4.26 radians and 244.0 degrees.
<h3>How to calculate the angle?</h3>
In Physics, the distance covered by an object in circular motion can be calculated by using this formula:
S = rθ
<u>Where:</u>
- r is the radius of a circular path.
- θ is the angle measured in radians.
Substituting the given parameters into the formula, we have;
1.87 = 0.44 × θ
θ = 1.87/0.44
θ = 4.26 radians.
Next, we would convert this value in radians to degrees:
θ = 4.26 × 180/π
θ = 4.26 × 180/3.142
θ = 244.0 degrees.
Read more on radians here: brainly.com/question/19758686
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This is true.
Hope this helps
Answer:
0.015
Explanation:
Total volume of water coming out = 1.33
Also volume = Cross sectional area*Length covered
Length covered = Velocity *time
=24.5*3.55
=86.97 meter
Let the cross sectional area be A.
1.33 = 86.97*A
A =0.015