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KiRa [710]
4 years ago
5

Which of the following options is correct and why?

Physics
1 answer:
Dimas [21]4 years ago
6 0

Answer:

Option (e) = The charge can be located anywhere since flux does not depend on the position of the charge as long as it is inside the sphere.

Explanation:

So, we are given the following set of infomation in the question given above;

=> "spherical Gaussian surface of radius R centered at the origin."

=> " A charge Q is placed inside the sphere."

So, the question is that if we are to maximize the magnitude of the flux of the electric field through the Gaussian surface, the charge should be located where?

The CORRECT option (e) that is " The charge can be located anywhere since flux does not depend on the position of the charge as long as it is inside the sphere." Is correct because of the reason given below;

REASON: because the charge is "covered" and the position is unknown, the flux will continue to be constant.

Also, the Equation that defines Gauss' law does not specify the position that the charge needs to be located, therefore it can be anywhere.

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116 N.

Explanation:

Given,

mass of the ball, m = 0.145 Kg

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Force is equal to change in momentum per unit time

F = \dfrac{m\Delta v}{\Delta t}

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F = 116 N

Force of the pitcher hand on the ball is equal to 116 N.

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Which is a derived unit?<br><br> A Meter<br><br> B Second<br><br> C Kilogram<br><br> D Newton
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4 years ago
Two gliders move toward each other on a linear air track, which we assume is frictionless. Glider A has a mass of 0.50 kg, and g
Nataly_w [17]

Answer:

-0.4 m/s

-3.552 m/s

Explanation:

m_1 = Mass of first glider = 0.5 kg

m_2 = Mass of second glider = 0.3 kg

u_1 = Initial Velocity of first glider = 2 m/s

u_2 = Initial Velocity of second glider = -2 m/s

v_1 = Final Velocity of first glider

v_2 = Final Velocity of second glider = 2 m/s

As the linear momentum of the system is conserved we have

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 2+0.3\times (-2)-0.3\times 2}{0.5}\\\Rightarrow v_1=-0.4\ m/s

The velocity of glider A is -0.4 m/s

u_1 = 0

u_2 = -5 m/s

v_2 = 0.92 m/s

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 0+0.3\times (-5)-0.3\times 0.92}{0.5}\\\Rightarrow v_1=-3.552\ m/s

The velocity of glider A is -3.552 m/s

8 0
3 years ago
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