Jjjhgggghujjnnbcxxddrtyyujjnn.
Answer:
a) 1. 1365 × 10⁻⁹N
b) 9.1862 × 10⁻⁴⁶N
c) 8.61 × 10⁻¹¹C/Kg
Explanation:
Ke = 8.99× 109 N.m2
/ C2
, G = 6.67 × 10-11 N. m2
/ kg2
a) F = Ke . q₁.q₂/r²
= (8.99× 109 N.m2
/ C2
) ×(1.60×10⁻¹⁹C)²/(4.50×10⁻¹⁰C)²
= 1. 1365 × 10⁻⁹N
b)
F = Gm₁m₂/r²
= (6.67× 10⁻¹¹)×(1.67×10⁻²⁷)²/(4.50×10⁻¹⁰)²
= 9.1862 × 10⁻⁴⁶N
The electric force is larger by 8.0497 ×10³⁷ times
c)
if Keq₁q₂/r² Gm₁m₂/r²,
with q₁=q₂ = q, and m₁ =m₂ = m
Then q/m =
= 
= 8.61 × 10⁻¹¹C/Kg
D. the wavelengths that the pigmented object after interacting with sunlight
For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .
A. The object is at rest. No. From F=ma, if F is not zero, the object can't remain at rest.
<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
C. The object's velocity can only increase. No. It might decrease.
D. The object is moving with constant velocity. No. From F=ma, if F is not zero, there must be acceleration.
<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
The scheme whereby occupants in a pair of shuttles is as follows
use a strong cable with large weight on the end
Then use the orbital naneuvering system(OMS) to set the whole work as spinning about their common center of gravity.
