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Vika [28.1K]
2 years ago
13

What is the mass of a cannonball if a force of 2,500 N gives the cannonball an acceleration of 200 m/s2? Question 5 options: 15.

0 kg 12. 5 kg 20 kg 25 kg.
Physics
1 answer:
djverab [1.8K]2 years ago
8 0

The mass of the given cannonball is 12.5 kg. Option B is correct.

<h3>What is Acceleration?</h3>

It is defined as the change in the direction and speed of the object. It is a vector quantity.

From, Newton's second law of motion

F = ma

Where,

F - force = 2,500 N

m - mass

a - acceleration =  200 m/s²


Put the values in the formula,

2500 = m \times 200 \\\\&#10;m = \dfrac {2500}{200}\\\\&#10;m = 12.5\rm \  kg &#10;

Therefore, the mass of the given cannonball is 12.5 kg.

Learn more about Acceleration:

brainly.com/question/2437624

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forsale [732]

Answer:

car d

Explanation:

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8 0
3 years ago
Derive an expression for the total mechanical energy of the system as the monkey reaches the top of the motion, Etop, in terms o
ipn [44]

Answer:

U =  0.5 * k *(x + d - h_max)^2 + m*g*h_max

Explanation:

Given:

- The extension in spring @ equilibrium = x m

- The spring constant = k

- The amount of distance pulled down = d

- mass of the toy = m

Find:

- The total mechanical energy E_top at the top position h_max in terms of the available variables.

Solution:

- First we need to determine the types of Energy that are in play:

- The Elastic potential Energy E_p in a spring is given:

                              E_p: 0.5 * k * (ext)

- In our case when the toy at the top most position h_max will have a net extension ext, by summing displacement of spring:

             ext = Equilibrium + distance pulled - h_max = (x + d - h_max)

Hence, the elastic potential energy will be:

                              E_p = 0.5 * k *(x + d - h_max)^2

- The gravitational potential energy E_g is given by:

                              E_g = m*g*h_max

Where, bottom most position is taken as reference (datum).

- The kinetic Energy E_k is given by:

                              E_k = 0.5*m*v_top^2

- Since we know that the maximum height is reached when velocity is zero

Hence,                   E_k = 0.5*m*0^2 = 0.

The total Energy of the system U is sum of all energies and play:

                               U = E_p + E_k + E_g

                               U =  0.5 * k *(x + d - h_max)^2 + m*g*h_max

8 0
4 years ago
Alex swims at an average speed of 45 m/min. How far does he swim in 1 min 24 secs?
ohaa [14]

Answer:

SOLUTION: Alex swim at an average speed of 45 meters per seconds how far does he swim in 1 minutes and 24 seconds. 1 minute and 24 seconds is 84 seconds. If he swims 45 meters every second and he swims for 84 seconds, that means he swims: 45 * 84 = 3780 meters in 1 minute and 24 seconds.

Explanation:

You multiply 45 by 84 and that is equal to 3,780.

3 0
3 years ago
A force of 48 newtons is required to start a 5.0 kg box moving across a horizontal concrete floor. What is the coefficient of st
Soloha48 [4]

1) The coefficient of static friction is 0.980

2) The coefficient of kinetic friction is 0.908

Explanation:

1)

In the first situation, the box is still at rest. There are two forces acting on the box:

- The force of push, F, forward

- The force of static friction, F_f

Since the box is in equilibrium we have

F_f = F (1)

The value of frictional force changes from zero to a maximum value which is given by:

F_f = \mu_s mg (2)

where

\mu_s is the coefficient of static friction

m is the mass of the box

g is the acceleration of gravity

So, if the force F needed to put the box in motion is 48 N, it means that this is also the maximum value of the force of friction. So, we can combine eq.(1) and (2) to find the coefficient of static friction:

\mu_s = \frac{F}{mg}

where:

F = 48 N

m = 5.0 kg

g=9.8 m/s^2

Substituting,

\mu_s = \frac{48}{(5.0)(9.8)}=0.980

2)

In this second situation, the object is already in motion, so the equation of motion is:

F-F_f = ma

where

F = 48 N is the force applied forward

a = 0.70 m/s^2 is the acceleration of the box

F_f = \mu_k mg is the force of kinetic friction, where

\mu_k is the coefficient of kinetic friction

We can therefore rearrange the equation to find the coefficient:

F-\mu_k mg = ma\\\mu_k mg = F-ma\\\mu_k = \frac{F-ma}{mg}=\frac{48-(5.0)(0.70)}{(5.0)(9.8)}=0.908

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7 0
3 years ago
Gravity is pulling on you downwards with a force which we call your weight. The reason why you aren't accelerating downwards is
VladimirAG [237]

Answer:

No.

Explanation:

This force, that avoids that our body be accelerated downwards in spite of the attractive force from the earth, is called the normal force, as it is always normal to the surface on which the object is placed.

It is not the "equal and opposite force" described by Newton's Third Law of motion, because, this law says that this force acts on both bodies simultaneously, ( as a pair) so, one force is the one exerted by Earth on the body (which we call weight) and the other is exerted by us on Earth (acting at the center of the Earth, upward).

Also, the case when the normal force is equal and opposite to gravity force, is a special case, when the surface is level, and the object is at rest in the vertical direction.

Normal force can adopt any value so the combination of external forces be compliant with Newton's 2nd Law.

7 0
4 years ago
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