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Masteriza [31]
3 years ago
7

What is a frame of reference? how is it used to measure motion? ​

Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

When an object changes position with respect to a frame of reference, the object is in motion. Distance measures the path taken.

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A solid cylinder with a mass of 2.72 kg and a radius of 0.083 m starts from rest at a height of 4.20 m and rolls down a 88.7 ◦ s
Bingel [31]

Explanation:

According to the law of conservation of energy ,    

             Potential energy = kinetic energy

   mgh = \frac{1}{2} \times mv^{2} + \frac{1}{2} \times I \times \omega^{2}

                  I = \frac{mr^{2}}{2}

          \omega = \frac{v}{r}

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]

             g \times h = \frac{3}{4} \times v^{2}

             9.8 \times 4.2 = \frac{3}{4} \times v^{2}

                  v = 7.4 m/s

thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.

5 0
3 years ago
What do active solar heat systems have that passive systems do not have?.
tamaranim1 [39]

Answer:

Passive solar heating uses building design to utilize sunlight, while active solar heating uses technology.

Explanation:

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5 0
2 years ago
If 28.0 J of work is done by an external force to move a charge from a potential of 8.0 V 8.0 V to a potential of 4.0 V , 4.0 V,
jonny [76]

Answer:

Change in electric potential energy is -28.0 J

Explanation:

Electric potential energy is defined as the work is done to move a charge particle from one position to another in space in the presence of other charge particle or electric potential.

                                               OR

Electric potential energy is also equal to the change in the configuration of the charge particles.

Thus,

Change in electric potential energy = - Work Done

According to the problem, Work Done is equal to 28 J. Thus,

Change in electric potential energy = -28 J  

5 0
3 years ago
A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the
LiRa [457]

The magnification of the ornament is 0.25

To calculate the magnification of the ornament, first, we need to find the image distance.

Formula:

  • 1/f = u⁻¹+v⁻¹.................... Equation 1

Where:

  • f = Focal length of the ornament
  • u = image distance
  • v = object distance.

make u the subject of the equation

  • u = fv/(f+v)................ Equation 2

From the question,

Given:

  • f = 8/2 = 4 cm
  • v = 12 cm

Substitute these values into equation 2

  • u = (12×4)/(12+4)
  • u = 48/16
  • u = 3 cm.

Finally, to get the magnification of the ornament, we use the formula below.

  • M = u/v.................. Equation 3

Where

  • M = magnification of the ornament.

Substitute these values above into equation 3

  • M = 3/12
  • M = 0.25.

Hence, The magnification of the ornament is 0.25

8 0
3 years ago
GUESS WHAT? I'LL MAKE YOU BRAINLIEST! EASY QUESTION!!
avanturin [10]

Here are the 2 reasons:

- Sun damages the eyes

Long-term, unprotected exposure to ultraviolet light from the sun can damage the retina. The retina is the back of the eye, where the rods and cones make visual images, which are then sent to the visual centers in the brain. Damage from exposure to sunlight can also cause the development of cloudy bumps along the edge of the cornea, which can then grow over the cornea and prevent clear vision. UV light is also a factor in the development of cataracts.

- Heat Exhaustion

According to the Centers for Disease Control and Prevention (CDC), heat exhaustion is the body’s response to excessive loss of water and salt, usually through excessive sweating. People working in a hot environment are at risk of heat exhaustion.

6 0
3 years ago
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