35. In the collision theory, a collision that leads to the formation of products is called an

5 cosas electricas que usan los zapateros los mecanicos y los electricistas ayuda plis rapido

IgorLugansk [536]

Destornilladores, alicates de corte diagonal, alicates de punta fina, alicates de bomba ajustable y cinta métrica con punta magnética

4 0

4 years ago

Mixture's and solutions

Anastaziya [24]

Mixtures and solutions... what?

8 0

3 years ago

Where are people mostly exposed to chemicals?

Vlad [161]

Answer:

people are mostly exposed to chemicals through their nose, mouth, eyes, and ears

Explanation:

they are the easiest way for anything, bad or good, to enter the body because people touch their face alot.

This might not answer what you were looking for but the other answer covered it pretty well so I thought I'd give you another angle to the question!

Hope this helps!!

4 0

3 years ago

When 0.215 mol of a gas is placed into a 34.25 mL container at 125.0°C, 1

horrorfan [7]

Answer:

205.12 atm

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

R = 0.0821 Latm/perK)

T = temperature (K)

n = number of moles (mol)

According to the information in this question;

P = ?

V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L

n = 0.215 mol

T = 125.0°C = 125 + 273 = 398K

Using PV = nRT

P = nRT ÷ V

P = (0.215 × 0.0821 × 398) ÷ (0.03425)

P = 7.025 ÷ 0.03425

P = 205.12 atm

8 0

3 years ago

Please answer these!!!

olasank [31]

Answer:

1.b. 2.5 mol

2.c.82.8%

3.d. synthesis

4.c . 2:2

5.d. 5 moles

6.c.5.02

7.d.3:1

8.d.2.68 moles

Explanation:

1.

$2RbNO_{3}\rightarrow 2RbNO_{2}+1O_{2}$

Here , 2 mole of RbNO3 will produce, 1 mole of O2

1 mole of RbNO3 will produce =

$\frac{1}{2}$ mole of O2

5 mole of RbNO3 will produce =

$\frac{1}{2}\times 5$

2 .

Molar mass of HCl = 1 + 35.45 = 36.45 gram

Molar mass of CO2 = 12 +32 = 44 gram

1 mole of the substance = molar mass

So , 1 mole of HCl = 36.45 gram

2 mole of HCl = 2 x 36.45 =72.9 gram

1 mole of CO2 = 44 gram

The given equation is :

$CaCO_{3}+2HCl\rightarrow CO_{2}+H_{2}O$

Here CaCO3 is the excess reagent and HCl is the limiting reagent

2 mole of HCl will produce = 1 mole of CO2

72.9 gram of HCl= 44 gram of CO2

so, 1 gram of HCl =

$\frac{44}{72.9}$ gram of CO2

Here we need to calculate the mass of CO2 in 200 gram of HCl.

So, 200 gram of HCl =

$\frac{44}{72.9}\times 200$ gram CO2

=120.71 gram CO2

this is the theoritical yield of CO2 = 120.71 gram

Experimental yield = 100 gram (given)

The percent yield is calculated by:

$=\frac{Experimental}{Theoritical}\times 100$

$=\frac{100}{120.71}100$

= 82.84%

3.Synthesis Reaction : Those reactions in which two or more substances combine to give a single product.

Here NH3 and HCl are combined and giving only one product = NH4Cl

4.

$2H_{2}+1O_{2}\rightarrow 2H_{2}O$

Hydrogen = H2

Water = H2O

Here Ratio of H2 to H2O is 2:2

5.The balanced equation is :

$1Ca(OH)_{2}+2HCl\rightarrow 1CaCl_{2}+2H_{2}O$

The number of atoms on left side should be equal to the right side:

Ca = 1

H = 4

O = 2

Cl = 2

Here, 2 moles of water(H2O) = 2 moles of HCl

So, 5 moles of water will give = 5 moles of HCl

6.

$2Ag(NO)_{3}+BaCl_{2}\rightarrow 2AgCl_{2}+BaNO_{3}$

Molar mass of AgNO3 = 169.87 g/mol

1 mol of AgNO3 = 169.87 gram

Molar mass of AgCl = 143.32 g/mol

1 mole of AgCl = 143.32 grams

According to the given equation ,

2 mole of AgNO3 will give = 2 mole of AgCl

1 mole of AgNO3 = 1 mole of AgCl

169.87 gram of AgNO3 = 143.32 gram of AgCL

1 gram of AgNO3 =

$\frac{143.32}{169.87}$

5.95 gram of AgNO3 =

$\frac{143.32}{169.87}\times 5.95$

= 5.02 grams

7. The mole ratio of Hydrogen (H2) to Nitrogen (N2):

$N_{2}+3H_{2}\rightarrow 2NH_{3}$

H2 = 3 mole

N2 = 1 mole

[H2]:[N2] = 3:1

8. The moles in a substance can be calculated by using :

$moles=\frac{Mass}{Molar\ mass}$

Mass of N2 = 75 grams (Given)

Molar mass = 28 gram

$moles=\frac{75}{28}$

Moles = 2.678 moles

8 0

3 years ago