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3 years ago

Based on the data, which statement describes the most reliable way to

Physics

2 answers:

jeka943 years ago

5 0

Answer:it’s A. right for ape x

Explanation:

marin [14]3 years ago

5 0

Answer: Just verifying the person above me is correct :)

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if i release one steel ball from the top of a ramp and the other ball from the 40cm mark will they have the same acceleration?

solniwko [45]

Answer:

Yes, they will also have the same acceleration. Acceleration is controlled by the amount of weight (def. amount of gravitational pull on a given object) that the ball has. For one ball to accelerate quicker than the other, it would need a propulsion element, which it does not.

Explanation:

6 0

2 years ago

A rocket is fired with an initial VELOCITY OF 100m/s at an angle of 55° above the horizontal, It explodes On the mountain Side 1

GuDViN [60]

Answer

688.32m and 277.44m

Explanation :

⠀

$\large{\maltese{\textsf{\underline{To find :-}}}}$

The X and Y coordinates of the rocket relative of firing

⠀

$\large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s$

⠀

$\Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}}$

⠀

The horizontal range of projectile at x.

⠀

$\sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t}$

⠀

$\large\textsf{\underline{Now substituting the required values}}$

⠀

$\sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}}$

⠀

The vertical position of projectile at y.

⠀

$\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2}$

⠀

$\textsf{ \large {\underline{Now substituting the required values}} }$

⠀

$\sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}}$

⠀

<h3>Henceforth, the distance at horizon is 688.32m and at vertical is 277.44m.</h3>

8 0

2 years ago

In the diagram, the Sun, Earth, and Moon are in perfect alignment. Which two conclusions can be drawn based on the diagram?

AysviL [449]

Answer:

I know one answer is an observer on earth sees a lunar eclipse

4 0

3 years ago

Read 2 more answers

A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of

ANEK [815]

Answer:

The distance the piece travel in horizontally axis is

L=3.55m

Explanation:

$a=2 \frac{rev}{s^{2}} \\h=0.820m\\r = 0.125 m
\\d=150rev$

$d= 155 rev = 155(2\pi ) = 310\pi rad$

$a= 2.0 \frac{rev}{s^{2} } = 2.0(2\pi ) = 4.0\pi \frac{rev}{s^{2} }$

$d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449$