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labwork [276]
4 years ago
14

A 500-watt vacuum cleaner is plugged into a 120-volt outlet and used for 30 minutes. How much current runs through the vacuum?

Physics
1 answer:
drek231 [11]4 years ago
3 0
P = IV,

P = Power in Watts, I = Current in Ampere, V = Voltage in Volts.

Current, I =   P/ V =  500 w/ 120v  ≈ 4.17 A 
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Calculate the ratio of the drag force on a passenger jet flying with a speed of 1200 km/h at an altitude of 10 km to the drag fo
Sonbull [250]

Answer:

2.267

Explanation:

Drag force is given by

F=\dfrac{1}{2}\rho Av^2C

C = Drag coefficient is constant

A = Area is constant

v_1 = Velocity of the passenger jet = 1200 km/h = \dfrac{1200}{3.6}\ \text{m/s}

v_2 = Velocity of the prop plane = \dfrac{1}{4}v_1

\rho_1 = Density of the air where the jet was flying = 0.38\ \text{kg/m}^3

\rho_2 = Density of the air where the prop plane was flying = 0.67\ \text{kg/m}^3

F\propto \rho v^2

\dfrac{F_1}{F_2}=\dfrac{\rho_1 v_1^2}{\rho_2 v_2^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{0.38 v_1^2}{0.67 (\dfrac{1}{4}v_1^2)}\\\Rightarrow \dfrac{F_1}{F_2}=2.267

The ratio of the drag forces is 2.267.

5 0
3 years ago
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Iteru [2.4K]

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7 0
3 years ago
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What factors could slow down a reaction time?
dybincka [34]

Answer: To keep it basic start with temprature and inhibitors such as drugs that slow enzymes

surface area, temperature, concentration, and the presence of catalysts and inhibitors

Explanation:To slow down a reaction, you need to do the opposite. Factors that can affect rates of reactions include surface area, temperature, concentration, and the presence of catalysts and inhibitors. Temperature - Changing the temperature of a chemical reaction also affects the reaction rate.

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3 years ago
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what is the mass of a in the cylinder if the cross sectional area has 0.4cm square and the vertical length of the liquid is 2cm
Leni [432]
Explanation is in a file
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3 years ago
Figure shows three blocks that are being pulled along a smooth horizontal surface. The masses of the blocks
Eva8 [605]

Answer:

The pulling force F is 200 N

Explanation:

We note that the tension in a rope between two or three blocks is given by the relation;

Where we have;

m₁ → T₁ → m₂ → T₂ → m₃ → F

T_1 = \dfrac{m_1}{m_1 + m_2 + m_3} \times F

T_2 = \dfrac{m_1 + m_2}{m_1 + m_2 + m_3} \times F

m₁ = 2 kg

m₂ = 4 kg

m₃ = 4 kg

T₂ = 120 N

Therefore, by substitution, gives;

2 kg → T₁ → 4 kg → 120 N → 4 kg → F

120 \ N = \dfrac{2 \ kg + 4 \ kg}{2 \ kg+ 4 \ kg+ 4 \ kg} \times F = \dfrac{6 \ kg}{10 \ kg} \times F

F = 120 N × (10 kg)/(6 kg) = 200 N

The pulling force F = 200 N.

7 0
3 years ago
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