1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AfilCa [17]
2 years ago
15

London dispersion forces decrease with increasing number of electrons decreasing number of electrons

Chemistry
1 answer:
ipn [44]2 years ago
6 0

Answer:

Increasing number of electrons

Explanation:

London dispersion forces are intermolecular forces that occur due to momentary shifts in the electron cloud of atoms or molecules.

London dispersion forces are most commonly observed as the predominant kind of intermolecular forces in non-polar substances.

Generally, it is observed that the strength of these London dispersion forces tends to increase as the number of electrons in the substance increases.

You might be interested in
A boy jumps into a cold swimming pool and his body temperature goes down. His muscles, blood vessels, and nervous system work to
mixas84 [53]

Answer:

balance

Explanation:

4 0
2 years ago
What is the mole ratio of NO2 to O2
Mazyrski [523]
The mole ratio is 4 NO2 to 3 O2; 4:3
8 0
3 years ago
Three chemistry students measured the length of a copper bar. The recorded lengths were 5.05 cm, 5 cm , and 5.1 cm, What is the
Salsk061 [2.6K]
5.05 + 5 + 5.1 = 15.15cm Then you just divide it by the amount of measurements you had like this:15.15 ÷ 3 = 5.04999971cm Then you can just round it to the 3rd figure: 5.05cm < And that's the mean/average length of the bar. :) (Or the one above if you want all of the decimals too) 
3 0
3 years ago
Antoine put some metal into a container with air. He closed the container. He measured the weight of the closed container with t
Mandarinka [93]

Answer:

the same

Explanation:

due to the law of conservation of mass, the mass will not change

7 0
3 years ago
If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0
2 years ago
Other questions:
  • Conceptual Checkpoint 21.22 Draw a mechanism of the following process. That is, draw a mechanism showing conversion of the conju
    11·1 answer
  • Which of the following is not a fossil fuel?<br><br> Natural Gas<br> Petroleum<br> Nitrogen<br> Coal
    11·2 answers
  • The atomic number of arsenic is 33 what is the electron configuration
    13·1 answer
  • What is a chemical reaction? ​
    10·1 answer
  • When an electron moves from a lower to a higher energy level does the electron gain or lose Quantum of energy
    13·1 answer
  • Give reason: The maximum covalence of boron is 4.​
    7·2 answers
  • Name the functional group in the
    15·1 answer
  • Please help me with this!
    12·2 answers
  • Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: ()Na2
    7·1 answer
  • Daniel is having a BBQ and he's making cheeseburgers. He has two packs of hamburger patties (each
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!