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3 years ago

hi, help me please with both number 4 and 5, please be sure of your answer, first to answer gets brainliest!

Chemistry

1 answer:

Evgesh-ka [11]3 years ago

8 0

Answer:

4. mutualism

5. commensalism

Explanation:

4. mutualism (they benefit off each other)

5. commensalism (the whale is unaffected)

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PLEASE HELP I WILL GIVE BRAINLIEST!!! Its due tonight at 12:00

Dmitry [639]

Answer:

Explanation:

we have only distance vs time graph so c is the right answer that cart is moving with constant speed of 0.5m/s

confirmed

first calculate distance which is from 2 to 5.5

5.5-2=3.5

apply the formula of velocity

v=s/t

v=3.5/7=0.5

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3 years ago

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Match the compounds as organic (O) or inorganic (I).

SashulF [63]

H2O2(I)
C6H6(O)
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C2H6(O)
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3 years ago

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Which of these gases will have the greatest density at the same specified temperature and pressure?

ch4aika [34]

Answer:

Neon

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Explanation:

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2 years ago

Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.

Oduvanchick [21]

Answer:

103.9 g

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First we convert 54.0 g of propane (C₃H₈) into moles, using its molar mass:

54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we convert 1.23 moles of C₃H₈ into moles of CO₂, using the stoichiometric coefficients:

1.23 mol C₃H₈ * $\frac{3molCO_2}{1molC_3H_8}$ = 3.69 mol CO₂

We convert 3.69 moles of CO₂ into grams, using its molar mass:

3.69 mol CO₂ * 44 g/mol = 162.36 g

And apply the given yield:

162.36 g * 64.0/100 = 103.9 g

7 0

3 years ago

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

Inessa [10]

Answer:

The answer is " $\bold{4.97 \times 10^{-2}}$ "

Explanation:

Please find the complete question in the attached file.

Equation:

$2SO_2+O_2 \leftrightharpoons 2SO_3$

at $t=0 3.3 \ \ \ \ \ \ \ \ \ \ 0.79$

at equilibrium $3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P$

$p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\$

$=\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}$

8 0

3 years ago

hi, help me please with both number 4 and 5, please be sure of your answer, first to answer gets brainliest!​

hi, help me please with both number 4 and 5, please be sure of your answer, first to answer gets brainliest!