Answer:

If we compare this function with the vertex form we see that:

So then the vertex would be 
And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

If we compare this function with the vertex form we see that:

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).
Step-by-step explanation:
We need to remember that the standard form for a parabola is given by the following equation:

And the vertex form is given by this formula:

And we want to find the vertex and if we have a maximum or minimum for each function. Let's begin with g(x)

If we compare this function with the vertex form we see that:

So then the vertex would be 
And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).
For the function f(x) we assume that we have the following equation:

If we compare this function with the vertex form we see that:

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).