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KengaRu [80]
3 years ago
11

Aplicar ley de Seno y Coseno

Physics
1 answer:
ycow [4]3 years ago
7 0

Answer:

Es 100000

Explanation: qppp-100

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A car starts from rest and accelerates from u seconds until it reaches a speed of 10ms
9966 [12]
Distance = speed* time

10x10^-3 *u + 10x10^-3 * 2u = 125

0.01u + 0.02u = 125

0.03u = 125
u = 4166.66666.... s

acceleration = (final velocity - initial velocity)/time

(10x10-3 - 0)/4167 = 2.3998 * 10^-6 m s-2
6 0
3 years ago
A yoyo is a toy made of three uniform density disks with a string wrapped around the middle disk. The middle disk has a mass m a
klasskru [66]

Answer:

if u are reading the answer i think u re safe

6 0
3 years ago
1) Two cars both moving at 27m/s (60mile/hr) pass each other on a road, one moving east the othe other west. 1a) both cars have
Igoryamba

Answer:

1a) True  1b) False

Explanation:

The definition of a car's velocity is the change of displacement between time, from here we can see that this is a vector, this means that it has magnitude and direction.

The definition of speed is the change of distance between the unit of time, as we see this magnitude is a scalar since distance is a scalar.

1 a) the car has the same speed, True since the magnitude is a scalar

1 b) the cars have the same speed. False since the magnitude is a vector, even if it has the same module it has different direction

5 0
3 years ago
An object starts from rest at time t = 0.00 s and moves in the +x direction with constant acceleration. The object travels 14.0
Sergio039 [100]

Answer:

The acceleration of the object is 9.3 m/s²

Explanation:

For a straight movement with constant acceleration, this equation for the position applies:

x = x0 + v0 t + 1/2 a t²

where

x = position at time t

x0 = initial position

v0 = initial velocity

a = acceleration

t = time

we have two positions: one at time t = 1 s and one at time t = 2 s. We know that the difference between these positions is 14.0 m. These are the equations we can use to obtain the acceleration:

x₁ = x0 + v0 t + 1/2 a (1 s)²

x₂ = x0 + v0 t + 1/2 a (2 s)²

x₂ - x₁ = 14 m

we know that the object starts from rest, so v0 = 0

substracting both equations of position we will get:

x₂ - x₁ = 14

x0 + v0 t + 1/2 a (2 s)² - (x0 + v0 t + 1/2 a (1 s)²) = 14 m

x0 + v0 t + 2 a s² - x0 -v0 t - 1/2 a s² = 14 m

2 a s² - 1/2 a s² = 14 m

3/2 a s² = 14 m  

a = 14 m / (3/2 s²) = <u>9.3 m/s² </u>

5 0
4 years ago
Brownian motion cannot be detected in colloids. True or false?
miskamm [114]
<span>Brownian motion is the random movement of colloidal particles suspended in a fluid. It is caused by random collisions of the molecules in the fluid medium. The particles in the solution or colloids are in constant random movement. A colloid has properties boundary to a homogenous and heterogeneous mixture. However in Brownian movement, the larger the size of a particle, the lesser its motion and the smaller the size of the particle, the higher is motion. Colloids in general have larger particle size and therefore it Brownian motion is sluggish. The statement is false.</span>
6 0
3 years ago
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