Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
1) 17, 29, 32, 9, 30, 14, 8, 39, 11, 32, 23<br>
Minimum :<br>
Maximum:<br>
Q1:<br>
Q2:<br>
Q3:
Lisa [10]
Answer:
Minimum: 8
Maximum: 39
Q1: 11
Q2: 23
Q3: 32
Step-by-step explanation:
Set the numbers into numerical order
8 9 11 14 17 23 29 30 32 32 39
Then separate into quarters
[8 9 11] [14 17 23] [29 30 32] 32 39
Answer:
Is there a picture for this?
Step-by-step explanation:
Answer:
y =
x + 6 or y =
x - 0.375
Step-by-step explanation:
For 2 lines to be perpendicular, their slopes must be <u>negative reciprocals</u>. In order to find the perpendicular of y - 4x - 6 = 0:
SLOPE INTERCEPT FORM: y = 4x + 6
SLOPE OF LINE A: m=4
SLOPE OF LINE B (the one you are looking for): m=
Since I don't know if you meant that they intercept on the x or y axis I will do both.
<u>y-axis</u>
y-6=
(x-0)
y =
x+6
<u>x-axis</u>
y-0=
(x-1.5)
y=
x-0.375