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PtichkaEL [24]
3 years ago
6

T he thermochemical equation for the reaction between hydrazine, N2H4, and dinitrogen tetroxide is given as: 2N2H4(2) N204 (1) 3

N2 (g) + 4H20 (g),AHO-1049 kJ What is the corresponding thermochemical equation for this reaction when 6 mol of nitrogen are formed?
Chemistry
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ

Explanation:

2N2H4(2) + N204 (1) --> 3N2 (g) + 4H20 (g),AHO-1049 kJ

when 6 mol of nitrogen are formed?

The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.

So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.

We have;

4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ

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The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

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Learn more about acid dissociation constant here:

brainly.com/question/22668939

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