ANSWER:
its oxidation number increases
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Answer: The compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Explanation:
If electronegativity difference between two atoms is less than 0.4 then bond formed is a pure covalent bond.
If electronegativity difference between two atoms is between 0.4 to 1.8 then bond formed is a polar covalent bond.
If electronegativity difference between two atoms is greater than 1.8 then bond formed is an ionic bond.
The electronegativity value of a nitrogen atom is 3.04. Hence, the electronegativity difference of
molecule is as follows.
As the electronegativity difference is 0 which is less than 0.4.
Hence, we can conclude that the compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Answer:
Oxidation is defined as the chemical process in which substance loses electron and hydrogen or gain oxygen while in the process of reduction, substance gains electron and hydrogen or loses oxygen.
So, from the given equation:
a. It is an oxidation reaction as Rb loses one elctron.
b. It is a reduction reaction as Te gains two electrons and become Te2-
c. It is a reduction reaction as H atom gains electrons.
d. It is an oxidation reaction as P loses 3 electrons.
Answer:iron and carbon
Explanation:I took the test it’s iron and carbon
Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46