Hi, the given question is incomplete, the complete question is:
It takes 4.37 J of heat to raise the temperature of Object A by 1°C, and 2.88 J to raise the temperature of Object B by 1°C. Suppose A and B are brought into contact. A is initially hotter. A is seen to cool down by 6.3°C . How would you calculate the rise in temperature of B?
Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
Answer:
The correct answer is 9.56 degree C.
Explanation:
Based on the given information, the given object A is initially hotter than object B, and the direct contact between them permits the transfer of heat between them. Based on the law of conservation of energy, the energy cannot be created nor be destroyed. In the given case, the energy, which is lost from object A can only be gained by object B.
Let us consider that both the objects exhibits equal mass, now in order to determine the transfer of energy between them there is a need to multiply the heat capacity with the temperatures. Therefore,
Energy lost by object A = Energy gained by object B
Heat capacity of object A × Temperature lost by object A = Heat capacity of object B × Temperature gained by object B
4.37 J/°C × 6.3 °C = 2.88 J × Tb
Tb = (4.37 J/°C × 6.3° C) / 2.88 J
Tb = 9.56 °C
