The Answer is B.
*NEGATIVE CHARGE, FOUND OUTSIDE THE NUCLEUS*
Based on Le Chatelier's principle, if a system at equilibrium is disturbed by changes in the temperature, pressure or concentration, then the equilibrium will shift in a direction to undo the effect of the induced change.
The given reaction is endothermic i.e, heat is supplied:
CH4(g) + H2O (g) + heat ↔ 3H2(g) + CO(g)
a) When the temperature is lowered, heat is being removed from the system. The reaction will move in a direction to produce more heat i.e. to the left.
Hence, the pressure of CH4 will increase and equilibrium will shift to the left
b) When the temperature is raised, heat is being added to the system. The reaction will move in a direction to consume the added heat i.e. to the right.
Hence, the pressure of CO will increase and equilibrium will shift to the right
Answer:
""the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.""
Explanation:
The answer to this question would be the last option - D) 414
Answer:
<u>167.2 g</u>
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. <u>Write the balanced chemical equation</u>
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3.<u> Multiply by the known volume of n (butane)</u>
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. <u>Use ideal gas law</u>
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5.<u> Find molar mass of CO2</u>
1 C x 12 + 2 O x 16 = 44.00
6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
