Answer:
Hydrogen in its metallic state (usually considered a nonmetal)
Lithium.
Sodium.
Potassium.
Rubidium.
Cesium.
Francium.
Explanation:
Answer: They all transmit energy
Explanation: Because they can all transfer energy, they can transmit it as well. Waves form because particles are disturbed by this transfer of energy.
<h2>
Answer: +1</h2>
<h3>
Explanation:</h3>
Nickel is the transitional metal in the compound
The overall charge of the compound Ni₃P
= the sum of the charges of element × the number number of atoms
<em />
<em>Because Ni₃P is a neutral compound, then the overall charge of the compound is zero.</em>
⇒ 3 (charge of Ni) + (charge of P) = 0
⇒ 3 (charge of Ni) = - (charge of P) <em> [Redox Rules: Group 15 </em>
<em> elements of -3.]</em>
⇒ 3 (charge of Ni) = - (-3)
(charge of Ni) = + 1
Answer:
CO(g) + H₂O(g) <=> CO₂(g) + H₂(g), (volume is decreased) .. No effect.
PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased) .. Shift left.
CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased) .. Shift right.
Explanation:
<em>Le Châtelier's principle</em><em> states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
<em />
<em>CO(g) + H₂O(g) <=> CO₂(g) + H₂(g) (volume is decreased)</em>
- When volume is decreased, the pressure will increase:
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 2.0 moles of gases.
So, decreasing the volume will have no effect on the reaction.
<em>PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
so, increasing the volume will shift the reaction left.
<em>CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (right side).
so, increasing the volume will shift the reaction right.
If you round the days hours to 24 then multiply 7 you get 168, and then if you multiply 1.2 you would get 201.6
so the answer would be 201.6 ml an hour