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Mashcka [7]
3 years ago
6

Help please, i don't know what the answer is but i accidently clicked D .....

Physics
1 answer:
GaryK [48]3 years ago
4 0

Answer:

You are right correct option is D.

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How is the strength of an electromagnet affected by the number of turns<br> of wire in a coil?<br> e
Anastasy [175]

Answer:I don't know

Explanation:

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3 years ago
What does "Position (m)” represent in the graph?
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<span>Position (m)” represent  <u>t</u></span><u>he dependent variable</u> in the graph.
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Investigations allow for the control of variables.
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Dependent / Response Variable: factor or condition in a experiment that changes as a result of the independent variable; often called the responding variable. ... Constant: factors or conditions in an experiment that are kept the same in as trials of the experiment. Control: a set up without the variable being tested.

 
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A 121-cm-long, 4.00 g string oscillates in its m = 3 mode with a frequency of 180 Hz and a maximum amplitude of 5.00 mm. What ar
Alex777 [14]

Answer:

0.8067 m

69.696 N

Explanation:

m = Mode = 3

M = Mass of string = 4 g

f = Frequency = 180 Hz

l = Length of string = 121 cm

Length of the string is given by

l=m\dfrac{\lambda}{2}\\\Rightarrow \lambda=2\dfrac{l}{m}\\\Rightarrow \lambda=2\times \dfrac{1.21}{3}\\\Rightarrow \lambda=0.8067\ m

The wavelength is 0.8067 m

Linear density is given by

\mu=\dfrac{M}{l}\\\Rightarrow \mu=\dfrac{4\times 10^{-3}}{1.21}

Speed of the wave

v=f\lambda\\\Rightarrow v=180\times 2\times \dfrac{1.21}{3}\\\Rightarrow v=145.2\ m/s

Speed of wave is given by

v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow T=\mu v^2\\\Rightarrow T=\dfrac{4\times 10^{-3}}{1.21}\times 145.2^2\\\Rightarrow T=69.696\ N

Tension is given by 69.696 N

8 0
3 years ago
A rock is falling off a cliff. The work that gravity performs on the rock is _____.
ivolga24 [154]

Answer:

Positive

Explanation:

Work is defined as the product of displacement of an object produced by the applied force and the component of force along that direction. Let us consider a situation in which the angle between the applied force and the displacement produced by it is at an angle θ. Let the magnitude of displacement be s and that of the applied force be F. Now, we have to find the component of force along the direction of the displacement. For that we have to resolve the force in to two components- one along the direction of displacement and other perpendicular to it. Since the angle between force and displacement is θ, the component of force along the direction of displacement will be Fcosθ and that perpendicular to it will be Fsinθ. Thus, b the definition of work, work done = Fcosθ x s = Fscosθ.

Now, coming to our question, the force here is gravitational force of attraction which is along downward direction. It is given in the question itself that the stone is falling down. Since the displacement and the applied force is along the same direction, angle between them, θ = 0.

Thus, work done = Fscosθ = Fscos0 = Fs (since cos0 =1)

Fs > 0

Thus, the work done is positive

7 0
4 years ago
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