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Fed [463]
2 years ago
12

Could someone please explain how to solve for the area?

Mathematics
2 answers:
aniked [119]2 years ago
8 0

9514 1404 393

Answer:

  280.6 square units

Step-by-step explanation:

The formula for the area of an n-gon with radius r is useful here:

  A = (n/2)r²sin(360°/n)

For your hexagon (n=6) with radius r=6√3, the area is ...

  A = (6/2)(6√3)²sin(360°/6) = 324sin(60°) = 162√3 ≈ 280.6 . . . square units

larisa86 [58]2 years ago
5 0

FORMULA:

•<u> </u><u>Area of regular hexagon</u> = 3r²sin60°

ANSWER:

We know the formula, so we just need to plug the respective value.

And 3 × (6√3)² × √3/2

  • 3 × 108 × √3/2
  • 324√3/2
  • 162√3
  • 162 × 1.732
  • 280.6 sq units.
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Need help with this please!!!
BARSIC [14]
I don't like dividing polynomials so I'm going to set x=1 and try them out.

(1-2-14+3)/4 = -3

Of the choices, only D gives -3 when x=1

~~~~~~~~~~~~~~~~~~~~~~

That's as much test-taking as math.  If we were to divide


             x^2 - 5x + 1
          -------------------------------
x + 3 |   x^3 - 2x^2 - 14x + 3
             x^3 + 3x^2
                      -5x^2 - 14x
                       5x^2 + 15x
                                      x + 3 
                                      x + 3

More work, still choice D


5 0
2 years ago
Wes used 49 quarts of oil when he changed the oil in 7 cars. Complete and solve the proportion to find how many quarts of oin he
aleksandrvk [35]
140 quarts of oil
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3 0
3 years ago
The mass of a penny was measured six times. The following data was reported:
Scrat [10]

Answer:

a) 8.103 g

b) 9.2948

c) 0

Step-by-step explanation:

Given:

Data reported:

9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 g

Now,

All the values except the 8.103 are above 9

Here the data 8.103 varies very much with respect to the other values

Hence,

a) the data 8.103 should be excluded

b) average value of the mass of the penny = \frac{9.314 + 9.215 + 9.323 + 9.278 + 9.344 }{5}

= 9.2948 g

c) Deviation = Mean - Data

9.2948 - 9.314 = -0.0192

9.2948 - 9.215 = 0.0798

9.2948 - 9.323 = -0.0282

9.2948 - 9.278 = 0.0168

9.2948 - 9.344 = -0.0492

Thus,

Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]

= 0

4 0
3 years ago
The seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean weight per plant is 15.0 pound
DanielleElmas [232]

Answer:

There are 118 plants that weight between 13 and 16 pounds

Step-by-step explanation:

For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)  

This can be translated into standard normal units by :  

Z = \frac{(X - \mu)}{\sigma}

Let X be the weight of the plant  

X ~ Normal( 15 , 1.75 )  

To find : P( 13 < X < 16 )  

= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})

= P( -1.142857 < Z < 0.5714286 )  

= P( Z < 0.5714286 ) - P( Z < -1.142857 )  

= 0.7161454 - 0.1265490  

= 0.5895965  

So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965  

Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200

                                            = 117.9193  

Therefore, There are 118 plants that weight between 13 and 16 pounds.

4 0
3 years ago
Find the measure of the angle indicated. 6
deff fn [24]

Answer:

1) m∠U = 90°

2) m∠C = 80°

Step-by-step explanation:

1) The given figure is a quadrilateral

The sum of the interior angles of  quadrilateral = 360°

∴ The sum of the interior angles of the given figure = 360°

Therefore, we have;

80° + 24·x + 4 + 6 + 21·x + 90° = 360°

80° + 45·x + 10  + 90° = 360°

x = (360°- (80° + 10° + 90°))/45 = 4

x = 4

m∠U = 6 + 21·x = 6 + 21 × 4 = 90

m∠U = 90°

2) The sum of the interior angles of the given quadrilateral = 360°

∴ 21·x + 6 + 20·x + 24·x + 4 + 21·x + 6 = 360°

86·x + 16 = 360°

x = (360° - 16°)/86 = 4

x = 4

m∠C = 20·x = 20 × 4 = 80

m∠C = 80°

3) In the figure, some angles are left out, therefore, more information on the remaining angles required

6 0
3 years ago
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