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tiny-mole [99]
3 years ago
7

Calculate (a) the pH of a 0.0250 M solution of phenylacetic acid, and (b) the pH of a 0.0500 M solution of sodium phenylacetate.

The pKa of phenylacetic acid is 4.31, and its structure is shown below.

Chemistry
1 answer:
almond37 [142]3 years ago
6 0

Answer:

Explanation:cool thre answer is 009000000000.1 because you have to add them so ye

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Identify the conjugate acid/base pairs in each of the following equations:
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(a) Pair 1: H₂S and HS⁻

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(d)  Pair 1: HNO₃ and NO₃⁻

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Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

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22.989769 u.

Explanation:

pls vote.......

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