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lozanna [386]
3 years ago
13

Lana is studying a chemical reaction in which the reactants propane (c3h8) and oxygen gas (o2) react to yield the products carbo

n dioxide (co2) and water (h2o). lana's teacher informs her that two molecules of propane and ten molecules of oxygen are reacting. the teacher then asks lana to assess how many molecules of carbon dioxide and water will be produced in the reaction. which answer choice correctly describes what lana should do to determine the answer to her teacher's question?
Chemistry
1 answer:
makvit [3.9K]3 years ago
8 0
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.

Equation:

                          C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O

Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.

As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).

Result:

                      ( C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O ) ₓ 2

                        2 C₃H₁₀ ⁺ 10 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  6 CO₂ ⁺ 8 H₂O

So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
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yawa3891 [41]

Answer:

a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

b. 0.957 g

Explanation:

Step 1: Write the balanced equation

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

Step 2: Convert 130.0 °C to Kelvin

We will use the following expression.

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K = 130.0°C + 273.15

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Step 3: Calculate the moles of O₂

We will use the ideal gas equation.

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n = P × V/R × T

n = 1 atm × 0.0730 L/0.0821 atm.L/mol.K × 403.2 K

n = 2.21 × 10⁻³ mol

Step 4: Calculate the moles of HgO that produced 2.21 × 10⁻³ moles of O₂

The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.

Step 5: Calculate the mass corresponding to 4.42 × 10⁻³ moles of HgO

The molar mass of HgO is 216.59 g/mol.

4.42 × 10⁻³ mol × 216.59 g/mol = 0.957 g

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