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Travka [436]
3 years ago
11

A persistent or nonvolatile chemical agent can: Select one: a. explode without warning and releases gases. b. remain in the envi

ronment for many weeks. c. remain on a surface for more than 24 hours. d. evaporate quickly when left on a surface
Chemistry
1 answer:
avanturin [10]3 years ago
5 0

Answer: A persistent or non-volatile chemical agent can remain on a surface for more than 24 hours.

Explanation:

Non-volatile substance is defined as the one which does not readily evaporate into its surrounding. Generally, a non-volatile substance has strong intermolecular forces between its molecules.

A non-volatile substance will take more than 24 hours to remain on the surface.

On the other hand, a substance with weak intermolecular forces present in its molecules will readily evaporate into the atmosphere.

For example, acetic acid is a volatile substance and quickly evaporates into the atmosphere.

Thus, we can conclude that a persistent or non-volatile chemical agent can remain on a surface for more than 24 hours.

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If I added 27 grams of salt to water and separated the solution
AfilCa [17]

Answer:

The correct answer is - 27 grams.

Explanation:

salts contain atoms (ions) like Na+ and Cl, these atoms are electrically charged that leads to a big crystal as they can stick together. Those are too heavy to evaporate.

When you heat the hot plate water evaporates but the salt does not leave vessel so, the concentration of salt in the water increases. In the end, the concentration of salt gets so high and the salt will begin to recrystallize into a solid. When all of the water is gone, you will have salt left behind in the same concentration.

Thus, the correct answer is - 27 grams.

7 0
3 years ago
How many grams of sodium can be reacted with 750 ml of a 6.0 m solution of sulfuric acid, h2so4?
devlian [24]
The balanced equation for the reaction between Na and H₂SO₄ is as follows;
2Na + H₂SO₄ ---> Na₂SO₄  + H₂
Stoichiometry of Na to H₂SO₄ is 2:1
the molar concentration of H₂SO₄ is 6.0 M
This means that in 1 L of H₂SO₄ - there are 6.0 mol of H₂SO₄
Therefore in 750 mL - \frac{6.0 mol* 750 mL}{1000mL }
Number of H₂SO₄ moles reacted - 4.5 mol
According to stoichiometry,
1 mol of H₂SO₄ reacts with 2 mol of Na
Therefore 4.5 mol reacts with 2x4.5= 9 mol of Na
Mass of Na reacted - 9 mol x 23 g/mol = 207 g of Na is required 
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