Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
<h3>
What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
Learn more about Escape Velocity here: brainly.com/question/13726115
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<h3><u>Answer;</u></h3>
Electromagnetic and transverse
<h3><u>Explanation</u>;</h3>
- Electromagnetic waves are types of waves which do not require material medium for transmission.
- Transverse waves are waves in which the vibration of particles is perpendicular to the direction of wave motion.
- All electromagnetic waves are transverse waves and travels with the speed of light. They include; gamma rays, x-rays, UV light, radio waves, and microwaves among others.
As we know that, f=ma where
f= net force
m=mass of body
a=acceleration
Substitute m and a in the formula and you will get the answer
Answer:
From left = 1.2L
From back = 0.9L
Explanation:
5 x = 3(L-X) + 2(2L-X)
X = 0.7L
Distance from left = 1.2L
7y = 2(L-X)+1(2L-x)
Y = 0.4L
Distance from back = 0.9L
