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3 years ago

Give an example of how energy from the sun gets into your cells

2 answers:

8 0

Examples of how Energy from the sun gets into your cells. Have you ever noticed that if you stayed under the sun(except noon which is the sun is really hot) you feel energized? Sun contains vitamins that can give your body more energy. Try not going out from your room the whole day, notice that your body feel weak and unhealthy. The same thing is happening to the plants and animals. They need the sun to be able to live healthy and longer.

Hope This Helps!! Have A Nice Daaay

bulgar [2K]3 years ago

6 0

We eat plants that use the energy from the sun to make food

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A motorcycle begins at rest and accelerates uniformly S7.9 we want to find a time to take the motorcycle to reach a speed of 100

Len [333]

The motorbike reaches 100 km/h in 3.5 seconds

Explanation:

The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the motorbike in this problem,

u = 0 (it starts from rest)

$v = 100 km/h = 27.8 m/s$ is the final velocity

$a=7.9 m/s^2$ is the acceleration

Solving for t, we find the time it takes for the bike to reach that velocity:

$t=\frac{v-u}{a}=\frac{27.8-0}{7.9}=3.5 s$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0

3 years ago

A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’

scZoUnD [109]

A charged particle moving in a magnetic field experiences a force equal to:

$\vec{F}=q\vec{v}\times \vec{B}$

Thus, the magnitude of the force that the proton experiences is given by:

$F=qvBsin\theta$

The magnetic field is perpendicular to the proton's velocity, therefore, we have $\theta=90^\circ$ . Replacing the given values, we obtain:

$F=1.6*10^{-19}C(300\frac{m}{s})(1T)sin(90^\circ)\\F=4.8*10^{-17}N$

3 0

3 years ago

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. how much time does it ta

Yuri [45]

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).

When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.

Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.

The equation of motion is stated as,

v = u + at

v² = u² + 2as

A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

1.5t = 6

t = 4 seconds

Hence, the time taken is 4 s.

The complete question is:

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

To know more about acceleration refer to: brainly.com/question/12550364

#SPJ4

8 0

1 year ago

Which of the following is required for work to be done on an object?

ad-work [718]

I think that in order for work to be done, the object must move in the direction of the force and move over a distance.

7 0

3 years ago

A car traveling with constant speed travels 150 km in 7200s. What is the speed of the car?

LiRa [457]

Speed= distance/time
Speed= 150000m/7200s=20.83m/s(cor.to.2d.p.)

7 0

3 years ago