When air is blown into the open pipe,
L = 
where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation
⇒λ=
Note here that n=1 is for fundamental, n=2 is first harmonic and so on..
⇒ third harmonic will be n=4
Given L=6m, n=4, solving for λ we get:
λ=
=3m
Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:
c=f.λ Or f= 
⇒f=
≈115 Hz
Answer:
a. distance = s x t
Explanation:
The equation we know for speed is speed = distance/time, shortened to s = d/t
If you want to find the distance, you'd rearrange the formula to make d the subject. To isolate d, multiply by t on both sides (since it's being divided on the right. This leads to
s x t = d, with d isolated on the right side.
Therefore, to find the distance an object travelled you'd use a. distance = s x t
Answer:
9.5 m/s
Explanation:
Distance, S = 150m
Acceleration, a = 0.3 m/s^2
Initial velocity, u = 0 m/s
Final velocity, v
Use kinematics equation
v^2 - u^2 = 2aS
v^2 - 0 = 2*0.3*150 = 90
v = sqrt(90) = 9.49 m/s
Answer:
For the first one its about 25 feet
Explanation:
