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zysi [14]
2 years ago
10

A dentist's chair with a person in it weighs 1675 N. The output plunger of a hydraulic system starts to lift the chair when the

dental assistant's foot exerts a force of 39 N on the input piston. Neglecting any difference in the heights of the piston and the plunger, what is the ratio of the area of the plunger to the area of the piston
Physics
1 answer:
Sphinxa [80]2 years ago
3 0

The ratio of the area of the plunger to the area of the piston will be 0.2323.

<h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

The presure at the output remains the same

\rm P_0=P_I \\\\\ \frac{F_0}{A_o} =\frac{F_I}{A_I} \\\\ \frac{A_0}{A_I} = \frac{F_0}{F_I} \\\\ \frac{A_0}{A_I} =\frac{39}{1675} \\\\ \frac{A_0}{A_I} =0.2323

Hence, the ratio of the area of the plunger to the area of the piston will be 0.2323.

To learn more about the pressure refer to the link;

brainly.com/question/356585

#SPJ1

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zavuch27 [327]

We could answer the question through the help of Faraday's Law of Induction: 

Volts induced = - N•dΦ/dt

where N is the number of turns, and

Φ is the magnitude of the magnetic field. 


V = IR, or R = V / I 


V = -18 * [13Wb – 4.5Wb] / 0.072s 


V = -2125 volts the sign just specifies direction 


R = -2125V / 190 A 


R = -11.1842105 Ω

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Two or more velocities add by vector sum.
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3 0
1 year ago
A tunnel has a length of 50 km. A car takes 20 min to travel between the two ends of the tunnel. What is the average speed of th
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7 0
3 years ago
A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering
Black_prince [1.1K]
<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y is the height of the stone at 6s (the value we want to find)

y_{o}=925ft is the initial height of the stone

V_{o}=20ft/s is the initial velocity of the stone

t=6s is the time  at which we need to find the height

g=32ft/s^{2} is the acceleration due to gravity

Having this clear, let's find y from (1):

y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2} (2)

Finally:

y=469ft This is the height of the stone at t=6s

4 0
2 years ago
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