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Hitman42 [59]
3 years ago
5

Tom has a new set of golf clubs. Using a club 8, the ball travels an average distance of 100 meters. Using a club 7, the ball tr

avels an average distance of 108 meters. Using a club 6, the ball travels an average distance of 114 meters. How far will the ball go if Tom uses a club 5? ASAP
Physics
1 answer:
cluponka [151]3 years ago
7 0
The answer is 118. 

hope this helps 

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elena-s [515]

Answer:

4.2 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(35 g) (9 m/s) + (75 g) (-7 m/s) = (35 g) (-15 m/s) + (75 g) v

315 g m/s − 525 g m/s = -525 g m/s + (75 g) v

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3 years ago
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Calculate its average speed in meters per second

Answer:

5.77 m/s

Explanation:

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Time= 8.8+1.6=10.4 s

Average speed= 60/10.4=5.769230769  m/s

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2 years ago
What is the charge on a hypothetical ion with 35 protons and 37 electrons?
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3 years ago
The density of mobile electrons in copper metal is 8.4 1028 m-3. Suppose that i = 4.6 1018 electrons/s are drifting through a co
Vesna [10]

Answer:

The time is 106.7 minute.

Explanation:

Given that,

Density = 8.4\times10^{28}\ m^3

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Length = 31 cm

We need to calculate the drift velocity

Using formula of drift velocity

v_{d}=\dfrac{I}{neA}

v_{d}=\dfrac{Ne}{tne\times\pi r^2}

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v_{d}=\dfrac{4.6\times10^{18}}{8.4\times10^{28}\times\pi\times(0.6\times10^{-3})^2}

v_{d}=4.842\times10^{-5}\ m/s

We need to calculate the time

Using formula for time

v_{d}=\dfrac{l}{t}

t=\dfrac{l}{v_{d}}

Where, l = length

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Put the value into the formula

t=\dfrac{31\times10^{-2}}{4.842\times10^{-5}}

t=6402.31\ sec

t=106.7\ minute

Hence, The time is 106.7 minute.

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