Explanation:
The relationship between electric force and distance between charged objects is given by the formula as follows :
![F=\dfrac{kq_1q_2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Bd%5E2%7D)
k is electrostatic constant and d is distance between charges
The electric force between charges is inversely proportional to the square of distance between them.
Answer:
Mass of the truck is
Kg
Explanation:
As we know that
Force is the product of mass and acceleration.
F = m * a
Here acceleration, a
m/s^2
Force, F
Newton
Mass = ![\frac{F}{a}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7Ba%7D)
Mass
Kg
To solve this problem it is necessary to apply the concepts related to entropy. Entropy can be defined as the change between heat energy and body temperature. For this case we will analyze the entropy in the cold body and later in the hot body. From there we will find the entropy difference
Entropy can be defined as,
![S = \frac{Q}{T}](https://tex.z-dn.net/?f=S%20%3D%20%5Cfrac%7BQ%7D%7BT%7D)
Here,
Q = Heat Flow
T = Temperature
The entropy of the hot reservoir goes down by
![S_1 = \frac{6400J}{610K}](https://tex.z-dn.net/?f=S_1%20%3D%20%5Cfrac%7B6400J%7D%7B610K%7D)
The entropy of the "cool" reservoir increases by
![S_2 = \frac{4200J}{320K}](https://tex.z-dn.net/?f=S_2%20%3D%20%5Cfrac%7B4200J%7D%7B320K%7D)
![\Delta S = S_2 -S_1](https://tex.z-dn.net/?f=%5CDelta%20S%20%3D%20S_2%20-S_1)
![\Delta S = \frac{4200J}{320K}-\frac{6400J}{610K}](https://tex.z-dn.net/?f=%5CDelta%20S%20%3D%20%5Cfrac%7B4200J%7D%7B320K%7D-%5Cfrac%7B6400J%7D%7B610K%7D)
![\Delta S = 13.125-10.492](https://tex.z-dn.net/?f=%5CDelta%20S%20%3D%2013.125-10.492)
![\Delta S = 2.633J/K](https://tex.z-dn.net/?f=%5CDelta%20S%20%3D%202.633J%2FK)
As expected, entropy increased in this process; the entropy lost by the hot side was less than the entropy gained by the cool side.