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bija089 [108]
3 years ago
8

What portion (division) of a meter stick is a centimeter?

Physics
2 answers:
Anastasy [175]3 years ago
8 0
A meter is 100 meters. So a hundredth of a meter stick is a centimeter.<span />
Nataliya [291]3 years ago
7 0

Answer

\frac{1}{100}

Explanation:

A meter stick is a tool used to measure length and distances. We know that one meter is equal to 100cm.

So,

100 cm = 1 meter

1 cm = \frac{1}{100} meter

Thus we can see that one hundredth of a meter stick is one centimeter.

The centimeter scale can be used to measure smaller lengths.

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The temperature of a gas is increased by 10degree Celsius. what is the corresponding change on Fahrenheit scale?​
Grace [21]

On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.

8 0
3 years ago
Two ions with masses of 4.39×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is
Ilia_Sergeevich [38]

Answer:

7.2 cm

Explanation:

magnetic field, B = 0.301 T

speed, v = 7.92 x 10^5 m/s

mass, m = 4.39 x 10^-27 kg

q = 1.6 x 10^-19 C

The radius of singly changed ion is given by

r = \frac{mv}{Bq}

where, m is the mass of ion, v be the speed of ion, B is the magnetic field and q be the charge

r = \frac{4.39\times 10^{-27}\times 7.92 \times 10^{5}}{0.301\times 1.6\times 10^{-19}}

r = 0.072 m

r = 7.2 cm

5 0
3 years ago
Why is Pluto considered less of an oddball planet now?
solmaris [256]

Answer:

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects

Explanation:

4 0
2 years ago
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750
White raven [17]

Answer:

the force exerted on the foot by the tibia would be 2975 N

Explanation:

Given the data in the question;

To maintain equilibrium between the foot and the ball vertically, the addition normal normal force N^> (750 N)  and the tension in the Achilles tendon F^>_{Achilles} (2225 N) must be equal to the force exerted on the foot by the tibia;

so

| N^> | + |F^>_{Achilles} | = | F^>_{Tibia} |

so force exerted on the foot by the tibia will be;

| F^>_{Tibia} | = |N^> | + |F^>_{Achilles} |

so we substitute IN OUR VALUES

| F^>_{Tibia} | = 750 N + 2225 N

| F^>_{Tibia} |  = 2975 N

Therefore, the force exerted on the foot by the tibia would be 2975 N

3 0
2 years ago
How will physical and/or chemical weathering contribute to create rounded shapes during spheroidal weathering?
Vilka [71]
Chemical weathering weakens the outer surfaces of rocks and its primary agent is water. Mechanical weathering is carried out by impact or attrition by water and air.
Both of these forms of weathering combine and cause rocks to obtain a spherical shape.The concentric layers of rock are combined to form structures known as saprolite.
6 0
3 years ago
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