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3 years ago

The stored energy an object has due to its position is energy.The stored energy an object has due to its position is energy.

Physics

2 answers:

kirza4 [7]3 years ago

5 0

<span>The stored energy an object has due to its position is _______energy. (Potential Energy)
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Licemer1 [7]3 years ago

3 0

Potential Energy (energy that is stored as a result of position or shape)

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A piece of driftwood moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves

pantera1 [17]

Answer:

It's A

Explanation:

As the waves progress through the medium, the particles they are made of move perpendicular to the direction in which the waves move. The particles do not move with the wave. So waves transmit energy but not matter as they progress through a medium.

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3 years ago

What relationship do you see between a star colour and temperature

Andrei [34K]

Answer:

Stars emit colors of many different wavelengths, but the wavelength of light where a star's emission is concentrated is related to the star's temperature - the hotter the star, the more blue it is; the cooler the star, the more red it is

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3 years ago

Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 1515 grams and velocity of 77 centimeters pe

Alexus [3.1K]

Answer:

The second kinetic energy is 162 J.

Explanation:

Given that,

Mass, $m_1=15\ g$

Velocity, $v_1=7\ cm/s$

Kinetic energy, $K_1=147\ ergs$

Mass, $m_2=10\ g$

Velocity, $v_2=9\ cm/s$

We need to find kinetic energy $K_2$ . Kinetic energy is given by :

$K=\dfrac{1}{2}mv^2$

So,

$\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J$

So, the second kinetic energy is 162 J.

4 0

3 years ago

In which object more force has to be applied to move in between two objects of mas 11

jeka94

Answer:

my butt

Explanation:

2x2 by the power of 10 divide that 98

4 0

3 years ago

A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km.At the bottom of the dive, the pilot has a sp

Yuliya22 [10]

Answer:

Force plane exert on pilot = 4270 N

Explanation:

first convert radius and speed to ms

using formula from force we know that

mass = weight/ gravity = 700 N/ 9.8N/kg= 71.4 kg

Fc= N-mg

N= Fc+ mg As Fc = mv²/R

N= mv²/R + mg

taking m common

N= m( v²/R +g)

= 71.4( (200)²/ 800 + 9.8 )

Force = 4270 N

3 0

3 years ago