Two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale is four times the reading on the celsius scale. the temperature of the liquid is:
Answer:
HERE'S MY UNDERSTANDING OF THE DIFFERENCE
Answer:
Try doing 90.0/2xT1 and that soud get u the answer of T2
Explanation:
I hope that helps!
The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.