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stiks02 [169]
3 years ago
14

Marlin wants to make his anemone home a safer place to live. He has created an

Chemistry
1 answer:
Leya [2.2K]3 years ago
3 0

Marlin conducted an experiment in which  independent variable is receiving an ointment and an dependent variable is number of anemone stings.

The people in the control group were neighbors in group B. The independent variable is the application of the ointment. The dependent variable is the number of  anemone stings. Marlin’s conclusion should be that the ointment was successful in reduce the stinging power of the anemone.  The eight people in group B reported feeling better because they believed that they were receiving the protective ointment.

An experiment must always have a dependent variable and an independent variable. The dependent variable is the variable that changes when the independent variable is manipulated.

In this case, the dependent variable is the number of anemone stings and the independent variable is the application of the ointment.

The experimental group (group A) received the ointment and a significant number of 30 participants reported feeling better meaning that the ointment was successful at protecting participants from anemone stings.

The control group (group B ) did not receive the ointment but received a placebo. Eight participants in that group reported feeling better because they believed that they received the protective ointment.

The experiment is successful and the ointment have been shown to protect people against anemone stings because more than 60% of the participants in the experimental group reported lesser anemone stings whereas only 16% of participants in the control group reported feeling better.

Learn more: brainly.com/question/967776

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kogti [31]

Answer:

c is right

Explanation:

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3 years ago
Covalent solutes are considered non-electrolytes. What does this mean for the conductivity of the solution? A) Non-electrolytes
iogann1982 [59]

Electrolytes are those which dissociates in solution and produces ions.

Ions can carry current,so Electrolytes conduct electiricity.

And non electrolytes are those which do not dissociate in solution and doesnt produce ions.

Since non electrolytes do not produce ions they cannot conduct electricity.

<u>Hence the right option is:</u>

B) Non-electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.  

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What is ionization energy
damaskus [11]
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. The first or initial ionization energy or Ei of an atom or molecule is the energy required to remove one mole of electrons from one mole of isolated gaseous atoms or ions
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3 years ago
Which of the following statements about metalloids is true?
Klio2033 [76]
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3 years ago
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Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
3 years ago
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