Answer:
2.895*10^24
Explanation:
mass of Oxygen give = 153.9g
molar mass of O2 molecule = 16*2=32g/mol
n= mole
To find the mole
n= mass/ molar mass
n= 153.9/32
n=4.81mol.
To find the number of molecules of o
Nm= number of molecule
Nn = Number of mole
NA = number of Avogados
Nm= Nn * NA
Nm= 4.81 *6.02*10^23
Nm= 2.895*10^24
MgCO3 + 2LiCl is the product of the above reaction.
Hope this helps you.
Answer:
V₂ = 495.89 mL
Explanation:
Given data:
Initial number of moles = 0.213 mol
Initial volume = 652 mL
Final number of moles = 0.162 mol
Final volume = ?
Solution:
V₁/n₁ = V₂/n₂
By putting values,
652 mL/0.213 mol = V₂ /0.162 mol
V₂ = 652 mL 0.162 mol /0.213 mol
V₂ = 105.62 mL.mol /0.213 mol
V₂ = 495.89 mL
