The answer to this would be d. Precipitation patterns .
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Answer:
Ksp = 0.1762
Explanation:
Applying
a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol
b) since 0.006mol is present in 0.012dm3 of HCl
It implies moles of borax
C) Concentration = 0.706M
Ksp = [0.5]^2[0.706]= 0.176
From the calculation, the standard free energy of the system is -359kJ.
<h3>What is the standard free-energy?</h3>
The standard free-energy is the energy present in the system. We have to first obtain the cell potential using the formula;
Ereduction - E oxidation = 0.96 V - 0.34 V = 0.62 V
Using the formula;
ΔG = -nFEcell
ΔG =-(6 * 96500 * 0.62)
ΔG =-359kJ
Learn more about free energy:brainly.com/question/15319033
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