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Natali5045456 [20]
3 years ago
12

How can we teach our kitty to behave properly​

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

I have no idea.

Explanation:

I just wanted to tell you I absolutely read this wrong.

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Which quantities indicate a direction and a magnitude?<br>Check all that apply.​
Korvikt [17]

Answer:

Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. Although a vector has magnitude and direction, it does not have position.

Explanation:

The only thing I found in my notes for this question was this although it isn't in your choices, I just hope this helps you and hope you get it right!

7 0
4 years ago
Red fox
Svetach [21]
In a food pyramid, the organism that has the least amount of total energy available is the one that is in the bottom or last. In this case, given the list of organisms above, the organism that would have the least amount of total energy available would be the RED FOX. The answer is option A. Hope this answer helps.
6 0
4 years ago
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A bullet is fired into the air at an angle of 30° to the horizontal. At the same time and from the same height,
enyata [817]

Answer:

The bullet that is fired will spend longer  in the air, hitting the ground after the  dropped bullet.

Explanation:

Using the equation: x =  x 0  +   v t

If we neglect the effects of air resistance, the horizontal motion is a constant velocity.

The horizontal displacement = (velocity X cosθ)

So, the fired bullet has to travel horizontally before falling which takes a  longer time compared to a bullet dropped where it is, height = 1/2 gt^2

gravity, g = 9.8 m/s2.

3 0
3 years ago
A rubber ball of mass 18.5 g is dropped from a height of 1.90 m onto a floor. The velocity of the ball is reversed by the collis
kati45 [8]

Answer:

J=0.211kg.m/s

Explanation:

The impulse-momentum theorem states:

J=\Delta p\\J=m(v_a-v-b)\\where:\\m=mass\\v_a=velocity\_after\\v_b=velocity\_before

The velocity before the impact is given by:

(v_b)^2=2.a.\Delta y\\v_b=\sqrt{2*(9.8m/s^2)1.90m}=6.10m/s(-\hat{j})

For the velocity after the impact:

(v_f)^2=(v_a)^2+2.a.\Delta y\\(0)^2=(v_a)^2+2.(-9.8m/s^s).(1.45m)\\\\v_a=\sqrt{2*9.8m/s^2*1.45m}\\v_a=5.33m/s(\hat{j})

so:

J=18.5*10^{-3}kg(5.33m/s(\hat{j})-6.10m/s(-\hat{j}))\\\\J=18.5*10^{-3}kg(5.33m/s(\hat{j})+6.10m/s(\hat{j}))\\\\J=0.211kg.m/s

3 0
4 years ago
How much time does it take for a car travelling at 5m/s in 21 metres
Paha777 [63]

Answer:

21/5 seconds or 4.2 seconds

Explanation:

Distance=Speed*Time

21=5 *Time

21/5=Time

4.2=time

7 0
3 years ago
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