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NikAS [45]
2 years ago
15

During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds.How many meters per second did the sprint increase with this amou

nt of acceleration
Physics
1 answer:
trasher [3.6K]2 years ago
3 0

During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds. The sprint increase with this amount of acceleration by 4.5 m/s.

<h3>What is acceleration?</h3>

Acceleration is the time rate of change of velocity.

Acceleration a = velocity v / time t

1.8 = v/2.5

v = 4.5 m/s

The sprint increase with this amount of acceleration by 4.5 m/s.

Learn more about acceleration.

brainly.com/question/12550364

#SPJ1

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To have a change in acceleration there has to be a change in velocity.
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3 years ago
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J. Ram travels 50 m on a straight road in 30 s. Hari covers the same distance
ira [324]

Explanation:

Explanation:

In the given question, there are two conditions.

Ram traveled 50 m in 30 seconds in a straight road.

Hari covers the same distance in the road; that means 50 m in 45 seconds

The formula for work w=\frac{d}{t}w=td

Ram's work w=\frac{50}{30}=1.66666w=3050=1.66666

Hari's work w=\frac{50}{45}=1.111w=4550=1.111

Ram is slower than Hari and the velocity of Ram is slower than Hari.

Ram has done less work than Hari.

Hence, Hari has done more work and he has more power than Ram.

6 0
2 years ago
If the cannonball weighs 5kg and the acceleration at 400 m/s², what is the acceleration of the 500kg cannon?
Elina [12.6K]
It is p d day we’ll be together if it weighs 5kg you divide by the accelerated pace 400 dividdd by 400 is 45 and 500 divided by 500 is 75 answer is 75.
3 0
3 years ago
A metal can containing condensed mushroom soup has mass 205 g, height 11.0 cm and diameter 6.38 cm. It is placed at rest on its
AlexFokin [52]

Answer: a) 0.000093 kg.m²

b) height of the can not required

Explanation:

It is placed at rest on its side, initial velocity = 0

s = ½ a t²

3 = ½ a 1.5²

a = 2.667 m/s²

torque T = f R = μ m g R cos Φ

according to Newton's second law of rotational motion,

T = I α = I (a/R) = μ m g R cos Φ

μ = I a/(R²m g cos Φ)

∑F = m a

m g sin Φ - μ m g cos Φ = m a

canceled all m, and remember that μ = I a/(R²m g cos Φ)

g sin Φ - I a/(R²m g cos Φ) g cos Φ = a

g sin Φ - I a/(R²m) = a

9.8 sin 24° - I (2.667)/(0.0319² * 0.205) = 2.667

3.86 - I x 2.667/0.000208 = 2.667

3.86 - 12822 x I = 2.667 m

I = 3.86 - 2.667 / 12822 = 1.193 / 12822 = 0.000093 kg.m²

6 0
3 years ago
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