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Sloan [31]
2 years ago
6

A 57-gram tennis ball moving at 70 miles per hour is hit with a 110-gram tennis racquet moving at 60 miles per hour. Which state

ment best compares the total amounts of mass and energy before and after impact? A. Because the velocities of the ball and racquet are unequal, there is more mass and energy after impact than there is before impact. B. Because the velocities of the ball and racquet are unequal, there is less mass and energy after impact than there is before impact. C. Because neither mass nor energy are conserved, the total amounts of mass and energy are different before and after impact. D. Because mass and energy are both conserved, the total amounts of mass and energy are the same before and after impact.
Physics
1 answer:
Whitepunk [10]2 years ago
5 0

Answer:

D. Because mass and energy are both conserved, the total amounts of mass and energy are the same before and after impact.

Explanation:

As we know that, the energy in motion is Kinetic Energy mathematically given as:

KE=\frac{1}{2} m.v^2

<u>Now, according to the law of conservation of energy:</u>

\frac{1}{2} m_1.u_1^2+\frac{1}{2} m_2.u_2^2=\frac{1}{2} m_1.v_1^2+\frac{1}{2} m_2.v_2^2

where:

m_1\ \&\ m_2 mass of racquet and ball respectively and u_1\ \&\ u_2 are their respective initial velocities.

v_1\ \&\ v_2 are the respective final velocities.

<u>Also the law of conservation of momentum is applicable in this case:</u>

m_1.u_1+ m_2.u_2= m_1.v_1+m_2.v_2

In this case the velocity of the lighter mass will get increases in the final condition.

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Answer:5101.35v

Explanation:

Radius of gold nucleus=7.3×10-15m and a charge of +79e

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U = 1/(4×3.142×Eo)×(qQ)/r

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3 0
3 years ago
Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod
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Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

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Given

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Answer:

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