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Xelga [282]
3 years ago
13

What is the energy of a 70 kg man running at 4 m/s? How much energy does the man have? *

Physics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

560J

Explanation:

Given parameters:

Mass of the man = 70kg

Velocity  = 4m/s

Unknown:

The amount of energy the man has = ?

Solution:

Energy is the ability to do work by a body. A body in motion is said to have kinetic energy and this can be derived using the expression below:

  K.E  = \frac{1}{2} m v²

m is the mass

v is the velocity

Insert the parameters and solve;

      K.E  =  \frac{1}{2} x 70 x 4²  = 560J

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photoshop1234 [79]

Answer:-2

Explanation:

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2 years ago
A child is holding a cup of hot tea. His mother, a physicist, warns him not to start running with the tea. According to Newton's
nalin [4]
If he stops running the tea is still going to be moving so it will spill on him.
3 0
3 years ago
A player at first base catches a throw traveling 38 m/s. The baseball, which has a mass of 0.145 kg, comes to a complete stop in
mixas84 [53]

Answer:

F = 39.36 N

Explanation:

given,

initial speed, u = 38 m/s

final speed, v = 0 m/s

mass of ball = 0.145 Kg

time, t = 0.14 s

Force = ?

using impulse formula

J = change in momentum

J = F x t

m(v - u) = F x t

0.145 x (0 - (-38)) = F x 0.14

F x 0.14 = 5.51

F = 39.36 N

force exerted by the ball is equal to 39.36 N.

5 0
3 years ago
A car that increases it's speed from 20 km/h to 100 km/h undergoes
enot [183]
If a car increases its speed from 20km/h to 100 km/h undergoes positive acceleration. Hope this helped!
3 0
3 years ago
A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.
jeka94
  • Mass of the elevator (m) = 570 Kg
  • Acceleration = 1.5 m/s^2
  • Distance (s) = 13 m
  • Let the force be F.
  • We know, F = ma,
  • Therefore, F = (570 × 1.5) N = 855 N
  • Angle between distance and force (θ) = 0°
  • We know, work done = F s Cos θ
  • Therefore, work done by the cable during this part
  • = (855 × 13 × Cos 0°) J
  • = (855 × 13 × 1) J
  • = 11115 J

<u>Answer</u><u>:</u>

<u>1</u><u>1</u><u>1</u><u>1</u><u>5</u><u> </u><u>J</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0
3 years ago
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