Q= m*c*ΔT
⇒ 209 J= 10.0 g* 4.18 J/(g*C)* (x- 23.0 C)
⇒ ...
⇒ x= 28.0 C
(3) 28.0<span>°C is the correct answer.
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Hope this helps~
Answer:
1.51834×10^22
Explanation:
Number of atom=Mass/Molar Mass × avogadros constant
2.3g/91.224g/mol × 6.203×10^23
Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
Since acetic acid or vinegar boils sooner than water and vinegar and water are highly miscible, we cant separate the two by filtration but one way is to use their volatilities. We can boil the solution at 100oC and thats the time, water remains in the container.
