You will have two birthdays this year.

Ok, guys here's the question. PLEASE HELP ME!!

Anit [1.1K]

Answer: the orange juice

Step-by-step explanation:

You would have to dived to get you the fractions to get 4 divide by 3 and you would get 1.33

6 0

3 years ago

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I'm not really understanding how to set this up

____ [38]

Answer: x = 21; y = 29.5

because 2y° and 59° are 2 opposing angles ⇒ 2y° = 59° ⇔ y = 29.5°

we also have: (3x - 4)° = 59° ( because of 2 parallel lines)

⇔ 3x = 59 + 4 = 63

⇔ x = 63/3 = 21

Step-by-step explanation:

4 0

3 years ago

Question in attachment

sdas [7]

Answer:

a₁ = 6

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a_{1}(r^{n}-1) }{r-1}$

where a₁ is the first term and r the common ratio

Here $S_{8}$ = 1530 and r = 2, thus

$\frac{a_{1}(2^{8}-1) }{2-1}$ = 1530 , that is

a₁ (256 - 1) = 1530

255a₁ = 1530 ( divide both sides by 255 )

a₁ = 6

8 0

3 years ago

Please answer this question now

Alexeev081 [22]

Answer:

$Area = 400.4 m^2$

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

$\frac{u}{sin(U)} = \frac{w}{sin(W)}$

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

$\frac{29}{sin(33)} = \frac{w}{sin(34)}$

Cross multiply

$29*sin(34) = w*sin(33)$

Divide both sides by sin(33) to make w the subject of formula

$\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}$

$\frac{29*sin(34)}{sin(33)} = w$

$29.77 = w$

$UV = w = 30 m$ (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

$area = \frac{1}{2}*u*w*sin(V)$

$= \frac{1}{2}*29*30*sin(113)$

$= \frac{29*30*sin(113)}{2}$

$Area = 400.4 m^2$ (to nearest tenth).

4 0

3 years ago

Hot dogs come in packages of 10 and hot dog buns come in packages of 8 . What is the least amount of product that you need to Bu

lubasha [3.4K]

This exercise is solved by finding the least common multiple between 10 and 8.

In fact, you have to buy a certain number $h$ of hot dog package, and you will have $10h$ hot dogs, since there are 10 hot dogs in each package. The key concept here is that the number of hot dogs you have in the end is a multiple of the number of hot dogs in each box.

Similarly, you have to buy a certain number $b$ of hot dog buns package, and you will have $8b$ hot dogs, since there are 8 hot dog buns in each package. Again, the key concept here is that the number of hot dog buns you have in the end is a multiple of the number of hot dog buns in each box.

Then, you want to have the same number of hot dogs and hot dog buns, i.e. you want

$10h = 8b$

but you also want $h$ and $b$ to be the first values to satisfy this equation.

This means that you want a multiple of 10 to equal a multiple of 8, and you want the smallest possible number which does the trick. Again, this is exactly the definition of the least common multiple.

To find the least common multiple of two numbers, find their prime factorization, and collect all the primes from both factorizations, with the highest exponent possible. Since $10 = 2\cdot 5$ and $8 = 2^3$ , the primes appearing are 2 and 5. The higher exponent for 2 is 3, and the only exponent for 5 is 1. So, the answer is $2^3\cdot 5 = 40$ .

So, if you buy 4 packages of hot dogs and 5 packages of hot dog buns, you will have 40 hot dogs and 40 hot dog buns, as requested.

4 0

3 years ago

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