Question

What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 liters

Answer 1

Answer:

0.56 liters

Explanation:

First we convert 0.80 grams of O₂ into moles, using its molar mass:

• 0.80 g ÷ 32 g/mol = 0.025 mol

At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we calculate the volume that 0.025 moles of O₂ gas would occupy:

• 0.025 mol * 22.4 L/mol = 0.56 L

Thus the answer is 0.56 liters.