42.34 g of water could be warmed from 21.4°C to 43.4°C by the pellet dropped inside it
Heat loss by the pellet is equal to the Heat gained by the water.
….(1)
where, 
is the heat gained by water
is the heat loss by pellet
= mCΔT
where m = mass of water
C = specific heat capacity of water = 4.184 J/g-°C
ΔT = Increase in temperature
ΔT for water = 43.4 - 21.4 = 22°C
= m × 4.184 × 22 …. (2)
Now
= 
×ΔT
where = Heat capacity of pellet = 56J/°C
Δ T for pellet = 43.4 - 113 =- 69.6°C
= 56 × -69.6 = -3897.6 J
From equation (1) and (2)
-m× 4.184 × 22 =-3897.6
m= 42.34 g
Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.
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Answer:
Absolute zero temperature: Absolute zero is the temperature at which a substance have very low internal energy or in other words no heat energy in the particle.
Explanation: The temperature is very low and the particles are very cold. On cooling, speed of particle decrease. On the Celsius scale, - 273.15 is the absolute zero and on the Kelvin scale, 0 k is the absolute zero. On absolute zero temperature, the movement in the particles occurs at very low speed near to zero.
Answer:
to measure seismic waves
Explanation:
it's used during earthquakes to tell how big on the richter scale the earthquake was
