Answer:
The molarity (M) of the following solutions are :
A. M = 0.88 M
B. M = 0.76 M
Explanation:
A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.
Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)
= 27 + 3(16 + 1)
= 27 + 3(17) = 27 + 51
= 78 g/mole
= 78 g/mole
Given mass= 19.2 g/mole
Moles = 0.246
Volume = 280 mL = 0.280 L
Molarity = 0.879 M
Molarity = 0.88 M
B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr
Molar mass of KBr = 119 g/mole
Given mass = 235.9 g
Moles = 1.98
Volume = 2.6 L
Molarity = 0.762 M
Molarity = 0.76 M
4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂
x=0.824*4/5=0.6592 mol
Answer:
1.52 L
Explanation:
P1V1T2=V2P2T1
V2=V1T2/T1
Fill in with given values then solve
We can check this by knowing that V and T at constant P have a proportional relationship. Hence, this is correct.
- Hope that helped! Please let me know if you need further explanation.
Since phosphorus is in the 5th group it has the ability to gain or lose electrons
The statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.
<h3>What is a pond?</h3>
Pond is an inland body of standing water, either natural or man-made, that is smaller than a lake.
A bog is an area of decayed vegetation (particularly sphagnum moss) which forms a wet spongy ground too soft for walking.
This means that a pond can become a bog when existing plants in the pond decays until the land becomes soft.
Therefore, the statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.
Learn more about ponds and bogs at: brainly.com/question/9715563
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