Answer:
Explanation:
Formula for the calculation of no. of Mol is as follows:
Molecular mass of Ag = 107.87 g/mol
Amount of Ag = 5.723 g
Molecular mass of S = 32 g/mol
Amount of S = 0.852 g
Molecular mass of O = 16 g/mol
Amount of O = 1.695 g
In order to get integer value, divide mol by smallest no.
Therefore, divide by 0.02657
Therefore, empirical formula of the compound =
Answer:
Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.
Explanation:
The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:
Time_________________ Amount
t=0_____________________x
t=10,000 years____________x/2
t=20,000 years___________x/4
During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.
I believe it was a blue mustang
Ionization energy refers to the amount of energy needed to remove an electron from an atom. Ionization energy decreases as we go down a group. Ionization energy increases from left to right across the periodic table.
<h3>What is ionization energy?</h3>
Ionization is the process by which ions are formed by the gain or loss of an electron from an atom or molecule.
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period but decreases along a group.
Smaller is the size of an atom more will be the force of attraction between its protons and electrons. Hence, more amount of energy is required to remove an electron.
Thus, we can conclude that the energy required to remove an electron from a gaseous atom is called ionization energy.
Learn more about the ionization energy here:
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