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Nookie1986 [14]
3 years ago
5

What is the percentage composition of carbon and hydrogen in ethane(c2h6,molecular mass 30.0)​

Chemistry
1 answer:
My name is Ann [436]3 years ago
5 0

Answer

% of C in C2H6= (2×12)/30×100=80%

% of H in C2H6= (3×2)/30×100=20%

Explanation:

2C+3H2-C2H6

nC=12, nH=1, nC2H6=30

2moles of C-1mole of C2H6

3moles of H-1 mole of C2H6

% of C in C2H6= (2×12)/30×100=80%

% of H in C2H6= (3×2)/30×100=20%

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It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

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no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

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  • Finally, we can get the volume of oxygen using the information:

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<em></em>

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