Answer:
384.2 K
Explanation:
First we convert 27 °C to K:
- 27 °C + 273.16 = 300.16 K
With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:
Where in this case:
We input the data:
300.16 K * 1600 m³ = T₂ * 1250 m³
And solve for T₂:
T₂ = 384.2 K
Answer : 135 grams of sodium has 5.869 moles.
Solution : Given,
Mass of sodium = 135 grams
Molar mass of sodium = 23 g/mole
Formula used :

Now put all the given values in this formula, we get

Therefore, the moles of sodium present in 135 grams of sodium is, 5.869 moles.
Answer:one gram by 1oC
Explanation: you will need to know the value of water's specific heat
Answer:
The primary role of the carbonic-acid-bicarbonate buffer system is to neutralize the hydronium ions forming carbonic acid and water when any acidic substance enter the bloodstream.
Explanation:
hope it helps.
1.75 moles of Solute or 1.75n.
To find this, you'll need to use the molarity equation which is M = 
List the given items to organize better:
M (Molarity) = .35
V (Volume) = 5L [must always be in Liters]
n (Moles) = ?
Now, for the equation, substitute the variables with the given numbers:
.35 = 
Isolate the variable by multiplying the volume, 5, onto both sides. This will give you the answer of:
1.75 = n
Hope this helps!