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Shkiper50 [21]
3 years ago
12

Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added ha

ve on the reliability of the results of your titration?
Chemistry
1 answer:
laiz [17]3 years ago
4 0

Answer: the reliability will be worse

Explanation:

Suppose we used 0.5 M NaOH to titrate our vinegar sample instead of 0.1 M.

Now by using 0.5M instead of 0.1M we are increasing the concentration of NaOH,

We know that  the moles used = Volume x concnetration.

so for the same no of moles, if the concentration increases, the volume decreases.

Hence it will consume less NaOH.

now Since the volume decreases, the titration volume of less number will increase the % error.

Therefore the reliability will be worse.      

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A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 30 m during the next 40 s.
Doss [256]

Answer:

\boxed{\text{0.76m/s}}

Explanation:

\text{Average speed} = \dfrac{\text{total distance}}{\text{total time}}

Total distance = 2 m + 30 m = 32 m

      Total time = 2 s  + 40 s   = 42 s

\text{Average speed} = \dfrac{\text{32 m}}{\text{42 s}} = \textbf{0.76 m/s}\\\text{The average speed of the object is $\boxed{\textbf{0.76m/s}}$}

5 0
4 years ago
Write the following numbers in standard notation. Use a terminal decimal point when needed.
maw [93]

In this case, when converting scientific notation to standard notation, we simply have to multiply the given number by 10^{x}x.

The answer will be 7.510^{2}  = 7.5100 = 750

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8 0
1 year ago
A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol
tatuchka [14]

Answer:

The pH of the solution is 1.38.

Explanation:

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Moles of HCl = \frac{0.614 g}{36.5 g/ mol}=0.01682 mol

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Concentration =\frac{Moles}{\text{Volume of solution in L}}

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.

[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M

HCl(s)+H_2O(l)\rightarrow H_3O^+(aq)+Cl^-(aq)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.

Then 0.04205 mol/L of HCl will give:

1\times 0.04205 M =0.04205 mol/L of hydronium ions.

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pH=-\log [H_3O^+]

pH=-\log [0.04205 M]=1.38

The pH of the solution is 1.38.

7 0
3 years ago
17 Which substance can not be broken down by a chemical change?(1) ammonia (3) propanal
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6 0
4 years ago
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Table 2 Heat of Reaction of NaOH (aq) and HCl(aq) Solution
kondaur [170]

Answer:

the molarity of NaOH is 1.10. And the molarity of HCl is 1.10. And the initial Temp=0.50(°c). and The final Temp= 1.10(°c)

8 0
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