When the reaction equation is:
HF ↔ H+ + F-
and when the Ka expression
= concentration of products/concentration of reactions
so, Ka = [H+][F-]/[HF]
when we assume:
[H+] = [F-] = X
and [HF] = 0.35 - X
So, by substitution:
6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X
∴ X = 0.015 M
∴[H+] = X = 0.015
when PH = -㏒[H+]
∴PH = -㏒0.015
= 1.8
Answer: its 15 its none of those
Explanation:
Answer:
7.335 moles of Cl₂ are required to react with 4.89 miles of Al.
Explanation:
Given data:
Moles of Al = 4.89 mol
Number of moles of Cl₂ required = ?
Solution:
Chemical equation:
2Al + 3Cl₂ → 2AlCl₃
Now we will compare the moles of Al and chlorine from balance chemical equation.
Al : Cl₂
2 : 3
4.89 : 3/2×4.89 =7.335 mol
Thus, 7.335 moles of Cl₂ are required to react with 4.89 miles of Al.
Answer:
20 protons and 20 electrons
Explanation:
Answer: 4.46 x 10^-4M
Explanation:
The pH of a solution is the concentration of hydrogen ion concentration in the solution. Mathematically, it is expressed as pH = -log(H+), where H+ is the concentration of hydrogen ion
On the pH scale, readings are from 1 to 14.
- pH values less than 7 are regarded as acidic. So, the solution with pH 3.35 is said to be acidic, and will produce hydrogen ions.
3.35 = -log(H+)
(H+) = Antilog (-3.35)
(H+) = 0.000446M
Place (H+) in standard form
(H+) = 4.46 x 10^-4M
Thus, the concentration of hydrogen ion in the solution with pH 3.35 is 4.46 x 10^-4M
