Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
0.5 is the decimal equivalent to 1/2
Answer:
4
Step-by-step explanation:
7*7-9*5
49-45
4
Answer:
one gadget costs $15.80
Step-by-step explanation:
Let w = cost of one widget
Let g = cost of one gadget
Given:
- Five widgets and three gadgets cost $109. 90
⇒ 5w + 3g = 109.9
Given:
- One widget and four gadgets cost $75. 70
⇒ w + 4g = 75.7
Rewrite w + 4g = 75.7 to make w the subject:
⇒ w = 75.7 - 4g
Substitute into 5w + 3g = 109.9 and solve for g:
⇒ 5(75.7 - 4g) + 3g = 109.9
⇒ 378.5 - 20g + 3g = 109.9
⇒ 378.5 - 109.9 = 20g - 3g
⇒ 268.6 = 17g
⇒ g = 15.8
Therefore, one gadget costs $15.80
To find the cost of one widget, substitute the found value for g into
w = 75.7 - 4g and solve for w:
⇒ w = 75.7 - 4(15.8)
⇒ w = 75.7 - 63.2
⇒ w = 12.5
Therefore, one widget costs $12.50
